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Ket [755]
3 years ago
13

I really need help with these questions, i don’t even have a clue how to do these.

Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
3 0

Answer:

231

Step-by-step explanation:

because the whole circle has an area of 360 so on the right side there is half and a little more so you would cut it in half so you have 180 and on the right side you still have a little left so thats about 10 so now you have 190 then you add 21 +20 you have 41 +190 =231 hope this helps

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3s² - 17s + 5 = 0<br> Quadratic equation or not a quadratic equation?
Thepotemich [5.8K]

Answer:

yes it is a quadratic equation

Step-by-step explanation:

a polynomial equation of the second degree.

hope it helps

5 0
3 years ago
A local Dot Dress Shop is selling a suit for $99. Due to changing styles the 1st markdown was 8% and the second markdown 25%. Th
Anit [1.1K]
The sale price = 99(1 - 0.1)(1 - 0.25)(1 - 0.08) = 99 * 0.9 * 0.75 * 0.92 = $61.48
8 0
3 years ago
1.4 km =<br> 140m<br> 1400m<br> 14m<br> d<br> 14000m
Usimov [2.4K]

Answer:140 meters

Step-by-step explanation:1km=100m, 1.4km times 100=140

6 0
3 years ago
Read 2 more answers
Solve the system of equations using subtraction.<br> 4x - 2y = 10<br> 4x + y = 19
Alex777 [14]

Answer:

y=3 x=4

Step-by-step explanation:

4x - 2y = 10

<u>4x + y = 19</u>

    -3y=-9

the 4x canceled out.

y=3

plug in y into one of the equations

4x + 3 = 19

4x=16

x=4

Hope this helps!

If not, I am sorry.

3 0
2 years ago
Read 2 more answers
An airplane flies due north from ikeja airport for 500km.It then flies on a bearing of 060 from a further distance of 300km befo
Nata [24]

Answer:

482 km

63.94 degrees

Step-by-step explanation:

to solve this question we will use the cosine rule. For starters, draw your diagram. From point A, up north is 500km and 060 from there, another 300. If you join the point from the road junction back to the starting point, yoou have a triangle.

Cosine rule states that

C = \sqrt{A^{2} + B^{2} -2AB   cos(c)  }

where both A and B are the given distances, 500 and 300 respectively, C is the 3rd distance we're looking for and c is the given angle, 060

solving now, we have

C = \sqrt{500^{2} + 300^{2} -2 * 500 * 300 cos(60)  }

C = \sqrt{250000 + 90000 - [215000   cos(60)  }]

C = \sqrt{340000 - [215000 * 0.5  }]

C = \sqrt{340000 - [107500  }]

C =\sqrt{232500}

C = 482 km

The bearing can be gotten by using the Sine Rule.

\frac{sina}{A} = \frac{sinc}{C}

sina/500 = sin60/482

482 sina = 500 sin60

sina = \frac{500 sin60}{482}

sina = 0.8983

a = sin^-1(0.8983)

a = 63.94 degrees

6 0
3 years ago
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