Answer:
1.74x10⁻⁵ V
Explanation:
n = 85.7 turns/cm => 8570 turns/metre
The field inside the long solenoid is given by B = μ₀ni
B = 4πx10⁻⁷ x 8570 x 0.175t² = 1.884x10⁻³ t²
dB/dt = 3.78x10⁻³ t
Cross-sectional Area'A'= 2.16 cm²=> 2.16 x 
m²
Now, rate of change of flux linkage '|Emf|' is given by:
|Emf| = d(NAB)/dt = NA dB/dt
|Emf| = 5 x 2.16 x x 3.78x10⁻³ t
|Emf| = 4.0824x10⁻⁶ t
Considering time 't' at which the current = 3.2A
, we have
3.2 = 0.175T²
T²
= 3.2/0.175
T = 4.28 s
|emf| = 4.0824x10⁻⁶ t => 4.0824x10⁻⁶ x4.28
|emf|= 1.74x10⁻⁵ V
Therefore,the magnitude of the emf induced in the secondary winding is 1.74x10⁻⁵ V
Answer:
v = 
the speed in the two planes will be the same since it does not depend on the angle of the same
Explanation:
In this exercise we are told that the two inclined planes have no friction force, so we can apply the conservation of energy for each one, we will assume that the initial height in the two planes is the same
starting point. Highest part of each plane
Em₀ = U = m g h
final point. Lowest part of each plane
= K = ½ m v²
as there is no friction, the mechanical energy is preserved
Em₀ = Em_{f}
mg h = ½ m v²
v =
As we can see, the speed in the two planes will be the same since it does not depend on the angle of the same
Answer:
A. When moving towards a high pressure center the pressure values increase in the equipment
B. This area is called high prison since the weight of the atmosphere on top is maximum
Explanation:
A) A high atmospheric pressure system is an area where the pressure is increasing the maximum value is close to 107 Kpa, the other side as low pressure can have small values 85.5 kPa.
When moving towards a high pressure center the pressure values increase in the equipment
B) This area is called high prison since the weight of the atmosphere on top is maximum
in general they are areas of good weather
The plane has a centripetal acceleration <em>a</em> of
<em>a</em> = <em>v</em> ²/<em>r</em>
where <em>v</em> is the plane's tangential speed and <em>r</em> is the radius of the circle. By Newton's second law,
<em>F</em> = <em>mv</em> ²/<em>r</em>
Solve for the mass <em>m</em> :
<em>m</em> = <em>Fr</em>/<em>v</em> ² = (3000 N) (18.3 m) / (55.0 m/s)² ≈ 18.1 kg
Venus goes through phases similar to those of earths moon.
