All categories

4 years ago

Question 3 (1 point) Question 3 Unsaved

Physics

1 answer:

zaharov [31]4 years ago

6 0

Q.3 the ans. increased urine output
Q.4 the ans. when you first wake-up
Q.5 the ans. water

You might be interested in

Determine the average velocity for an object that moves from x = 3.5 m to x =

SashulF [63]

-1.5-3.5 /2

-5/2=-2.5 m/s

4 0

3 years ago

Which of the following is not a

marissa [1.9K]

Answer:

polarization

Explanation:

6 0

3 years ago

A satellite orbits the Earth in an elliptical orbit. At perigee its distance from the center of the Earth is 22500 km and its sp

aleksley [76]

Answer:

$6.09294\times 10^{24}\ kg$

Explanation:

K = Kinetic energy

$v_p$ = Perigee speed = 4280 m/s

$v_a$ = Apogee speed = 3990 m/s

$r_p$ = Perigee Distance = 22500000 m

$r_a$ = Apogee Distance = 24100000 m

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

M = Mass of Earth

m = Mass of satellite

In this system the kinetic and potential energies are conserved

$K_p+P_p=K_a+P_a\\\Rightarrow \frac{1}{2}mv_p^2-\frac{GMm}{r_p}=\frac{1}{2}mv_a^2-\frac{GMm}{r_a}\\\Rightarrow \frac{1}{2}m(v_p^2-v_a^2)+GMm\left(\frac{1}{r_a}-\frac{1}{r_p}\right)=0\\\Rightarrow M=\frac{v_a^2-v_p^2}{2G}\times \left(\frac{1}{r_a}-\frac{1}{r_p}\right)^{-1}\\\Rightarrow M=\frac{3990^2-4280^2}{2\times 6.67\times 10^{-11}}\times \left(\frac{1}{24100000}-\frac{1}{22500000}\right)^{-1}\\\Rightarrow M=6.09294\times 10^{24}\ kg$

The mass of the Earth is $6.09294\times 10^{24}\ kg$

3 0

4 years ago

How do u convert 7.68 cal/sec to kcal/min

stich3 [128]

First you have to convert 7.68 cal/sec to cal/min to do that, just multiply by 60 So it will be 460.8 cal/min now convert that to kcal/min kcal = kilocalories = 1000 calories. so just divide by 1000 and youll have your answer in kcal/min

5 0

4 years ago

Read 2 more answers

What is the degrees in 3 full turns

Aleks04 [339]

1080 degrees buddy bye

3 0

3 years ago

Read 2 more answers