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Rudik [331]
3 years ago
12

Question 3 (1 point) Question 3 Unsaved

Physics
1 answer:
zaharov [31]3 years ago
6 0
Q.3  the ans. <span>increased urine output
</span>Q.4  the ans. <span>when you first wake-up
Q.5  the ans. water</span>
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12. A frain moves from rest to a speed of 25 m/s in 30.0 seconds. What is its acceleration?
ziro4ka [17]
  • initial velocity=u=0m/s
  • Final velocity=v=25m/s
  • Time=t=30s

\\ \tt\longmapsto Acceleration=\dfrac{v-u}{t}

\\ \tt\longmapsto Acceleration=\dfrac{25-0}{30}

\\ \tt\longmapsto Acceleration=\dfrac{25}{30}

\\ \tt\longmapsto Acceleration=0.8m/s^2

6 0
2 years ago
Convert 2 days into second​
eduard

Answer:

<em><u>172,000 second </u></em>

<em><u>I'M</u></em><em><u> </u></em><em><u>NOT</u></em><em><u> </u></em><em><u>SURE</u></em><em><u> </u></em><em><u>THAT</u></em><em><u> </u></em><em><u>THIS</u></em><em><u> </u></em><em><u>IS</u></em><em><u> </u></em><em><u>RIGHT</u></em><em><u> </u></em><em><u>OR</u></em><em><u> </u></em><em><u>WRONG</u></em><em><u> </u></em><em><u> </u></em><em><u>IF</u></em><em><u> </u></em><em><u>IT'S</u></em><em><u> </u></em><em><u>WRONG</u></em><em><u> </u></em><em><u>THEN</u></em><em><u> </u></em><em><u>SORRY</u></em><em><u> </u></em>

3 0
2 years ago
Read 2 more answers
A radio station broadcasts its music with waves at a frequency of 7.34 x 10²Hz. These radio waves travel at a speed of 3.00x 10%
Lorico [155]

Answer:

See below

Explanation:

<u>I will use   3 x 10^8 m/s for speed or wave</u>

speed = wavelength * frequency

3 x 10^8  = w * 7.34 x 10^2     <====== are you sure this isn't KILO Hz ?

w = <u>408719. 3 meters   </u>

4 0
1 year ago
It has been suggested that rotating cylinders about 10 mi long and 5.9 mi in diameter be placed in space and used as colonies. T
tekilochka [14]

Answer:

ω = 0.05 rad/s

Explanation:

We consider the centripetal force acting as the weight force on the surface of the cylinder. Therefore,

Centripetal Force = Weight\\\frac{mv^{2}}{r} = mg\\\\here,\\v = linear\ speed = r\omega \\therefore,\\\frac{(r\omega)^{2}}{r} = g\\\\\omega^{2} = \frac{g}{r}\\\\\omega = \sqrt{\frac{g}{r}}\\

where,

ω = angular velocity of cylinder = ?

g = required acceleration = 9.8 m/s²

r = radius of cylinder = diameter/2 = 5.9 mi/2 = 2.95 mi = 4023.36 m

Therefore,

\omega = \sqrt{\frac{9.8\ m/s^{2}}{4023.36\ m}}\\\\

<u>ω = 0.05 rad/s</u>

7 0
3 years ago
Describe how energy is transferred from the sun to producers and then to consumers
Sphinxa [80]
Producers to primary consumers to secondary consumers to tertiary consumers to carnivores
7 0
3 years ago
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