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Rudik [331]
3 years ago
12

Question 3 (1 point) Question 3 Unsaved

Physics
1 answer:
zaharov [31]3 years ago
6 0
Q.3  the ans. <span>increased urine output
</span>Q.4  the ans. <span>when you first wake-up
Q.5  the ans. water</span>
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True or False: The arrows on a motion map should point in the directions of motion.
slavikrds [6]

Answer:

true,true,false

Explanation:

its false because if it is equal it would show an arrow pointing left and a 20 and the same for the right

3 0
2 years ago
A Chinook (King) salmon (Genus Oncorynchus) can jump out of water with a speed of 6.75 m / s . If the salmon is in a stream with
Pepsi [2]

Answer:

The maximum height that the fish can jump is 2.19 m.

Explanation:

Hi there!

Please, see the attached figure for a better understanding of the problem.

The motion of the salmon is a parabolic one because when it jumps, it already has a horizontal velocity (see figure).

The position and velocity vectors of the salmon at a time t, can be calculated as follows:

r = (x0 + v0x · t, y0 + v0y · t + 1/2 · g · t²)

v = (v0x, v0y + g · t)

Where:

r = position of the salmon at time t.

x0 = initial horizotal position.

v0x = initial horizontal velocity.

t = time.

y0 = initial vertical position.

v0y = initial vertical velocity.

g = acceleration of gravity.

Looking at the figure, notice that at the maximum height, the vertical velocity is zero (because the velocity vector is horizontal). Using the equation of the vertical component of the velocity, we can obtain the time at which the salmon is at its maximum height:

vy = v0y + g · t

To find the initial vertical velocity, v0y, let´s look at the figure. Notice that the initial velocity is the hypotenuse of the triangle formed with the horizontal velocity and the vertical velocity. Then:

v0² = v0x² + v0y²

Solving for v0y:

v0y = √(v0² - v0x²)

v0y = √((6.75 m/s)² - (1.65 m/s)²)

v0y = 6.55 m/s

Now, using the equation of the vertical component of the velocity at the maximum height (vy = 0):

vy = v0y + g · t

0 = 6.55 m/s + (-9.8 m/s²) · t

-6.55 m/s / -9.8 m/s² = t

t = 0.67 s

Now, using the equation of the vertical position at t = 0.67 s, we can find the maximum height:

y = y0 + v0y · t + 1/2 · g · t²

y = 0 m + 6.55 m/s · 0.67 s + 1/2 · (-9.8 m/s²) · (0.67 s)²

y = 2.19 m

The maximum height that the fish can jump is 2.19 m.

4 0
3 years ago
2. What is the resistance expected on a heater that is feed by 480V AC and the Electric Power is 4.6kW? ​
Korvikt [17]

The resistance expected of the heater is 50.1 ohms.

<h3>What is resistance?</h3>

Resistance can be defined as the opposition to the flow of electric current in an electric circuit. The S.I unit of resistance is Ohms (Ω).

To calculate the resistance of the heater, we use the formula below.

<h3>Formula:</h3>
  • R = V²/P............. Equation 1

Where:

  • R = Resistance of the heater
  • P = Power of the heater
  • V =  Voltage supplied to the heater

From the question,

Given:

  • V = 480 V
  • P = 4.6 kW = 4600 W

Substitute these values into equation 1

  • R = (480²)/4600
  • R = 50.1 ohms.

Hence, the resistance expected of the heater is 50.1 ohms.

Learn more about resistance here: brainly.com/question/17563681

3 0
2 years ago
a lump of putty and a rubber ball have equal mass. both are thrown with equal speed against a wall. the putty sticks to the wall
RUDIKE [14]
The bouncy ball experiences the greater momentum change.

To understand why, you need to remember that momentum is actually
a vector quantity ... it has a size AND it has a direction too.

The putty and the ball have the same mass, and you throw them
with the same speed.  So, on the way from your hand to the wall,
they both have the same momentum.
Call it " M in the direction toward the wall ".

After they both hit the wall:

-- The putty has zero momentum.
    Its momentum changed by an amount of  M .

-- The ball has momentum of " M in the direction away from the wall ".
    Its momentum changed by an amount of  2M .
5 0
3 years ago
Read 2 more answers
WGVU-AM is a radio station that serves the Grand Rapids, Michigan area. The main broadcast frequency is 1480kHz. At a certain di
Yuki888 [10]

Answer:

a

  \lambda  =  202.7 \  m

b

  w =  9.3 *10^{6} \  rad/s

c

  k = 0.031 m^{-1}

d

  E_{max} = 9.0 *10^{-3} \  V/m

Explanation:

From the question we are told that  

       The frequency of the radio station is  f=  1480 \  kHz  =  1480 *10^{3}\ Hz

         The magnitude of the magnetic field is  B  =  3.0* 10^{-11} \  T

Generally the wavelength is mathematically represented as

          \lambda  =  \frac{c}{f}

Here c is the speed of light with value  c =  3.0 *10^{8} \ m/s

So

        \lambda  =  \frac{3.0 *10^{8}}{ 1480 *10^{3}}

=>      \lambda  =  202.7 \  m

Generally the angular frequency is mathematically represented as

       w =  2 \pi * f

=>   w =  2 * 3.142 *  1480 *10^{3}

=>   w =  9.3 *10^{6} \  rad/s

Generally the wave number is mathematically represented as        

=>      k = \frac{2 \pi }{\lambda}

=>      k = \frac{2  *  3.142  }{ 202.7}

=>      k = 0.031 m^{-1}

Generally the amplitude of the electric field at this distance from the transmitter is mathematically represented as

         E_{max} = c *  B

=>      E_{max} = 3.0 *10^{8} *   3.0* 10^{-11}

=>      E_{max} = 9.0 *10^{-3} \  V/m

3 0
2 years ago
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