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Hatshy [7]
3 years ago
7

Angles In Triangles ​

Mathematics
2 answers:
Elden [556K]3 years ago
7 0

Answer:

It's a isosceles triangle, i am not saying its clearly implied in the diagram with the red lines.... Which state that both the sides have same length

Hence if on ne side makes 55 with the base therefore the side with same length will make 55 with the base too

Hence its

55+55+x=180

X= 180-55-55

X= 70 degree

Therefore x is 70 degree

alexira [117]3 years ago
3 0
Answer:
x = 70

Explanation:
55 + 55 = 110
180 - 110 = 70
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Bella earned the federal minimum wage in the year 2008. During that time, she worked 37.5 hours per week. How much money did she
Mariana [72]

Answer:

Belle's weekly earnings per week in 2008: $245.7

Step-by-step explanation:

The federal minimum wage in the year 2008 was: $6.55

She worked 37.5 hours per week.

She earn each week:

weekly earnings = 6.55*37.5=245.7

7 0
2 years ago
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What is a tenth of a decimal ?
trapecia [35]
One decimal place to the left decimal point is the place.
8 0
3 years ago
HELLLP MEEEEEEEE PLEASE
jolli1 [7]

Answer:

Each side is 15 ft

Step-by-step explanation:

The area of a square is given by

A = s^2 where s is the side length

225 ft^2 = s^2

Take the square root of each side

sqrt ( 225 ft^2) = sqrt ( s^2)

15 ft = s

Each side is 15 ft

6 0
3 years ago
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Suppose small aircraft arrive at a certain airport according to a Poisson process with rate a 5 8 per hour, so that the number o
timurjin [86]

Answer:

(a) P (X = 6) = 0.12214, P (X ≥ 6) = 0.8088, P (X ≥ 10) = 0.2834.

(b) The expected value of the number of small aircraft that arrive during a 90-min period is 12 and standard deviation is 3.464.

(c) P (X ≥ 20) = 0.5298 and P (X ≤ 10) = 0.0108.

Step-by-step explanation:

Let the random variable <em>X</em> = number of aircraft arrive at a certain airport during 1-hour period.

The arrival rate is, <em>λ</em>t = 8 per hour.

(a)

For <em>t</em> = 1 the average number of aircraft arrival is:

\lambda t=8\times 1=8

The probability distribution of a Poisson distribution is:

P(X=x)=\frac{e^{-8}(8)^{x}}{x!}

Compute the value of P (X = 6) as follows:

P(X=6)=\frac{e^{-8}(8)^{6}}{6!}\\=\frac{0.00034\times262144}{720}\\ =0.12214

Thus, the probability that exactly 6 small aircraft arrive during a 1-hour period is 0.12214.

Compute the value of P (X ≥ 6) as follows:

P(X\geq 6)=1-P(X

Thus, the probability that at least 6 small aircraft arrive during a 1-hour period is 0.8088.

Compute the value of P (X ≥ 10) as follows:

P(X\geq 10)=1-P(X

Thus, the probability that at least 10 small aircraft arrive during a 1-hour period is 0.2834.

(b)

For <em>t</em> = 90 minutes = 1.5 hour, the value of <em>λ</em>, the average number of aircraft arrival is:

\lambda t=8\times 1.5=12

The expected value of the number of small aircraft that arrive during a 90-min period is 12.

The standard deviation is:

SD=\sqrt{\lambda t}=\sqrt{12}=3.464

The standard deviation of the number of small aircraft that arrive during a 90-min period is 3.464.

(c)

For <em>t</em> = 2.5 the value of <em>λ</em>, the average number of aircraft arrival is:

\lambda t=8\times 2.5=20

Compute the value of P (X ≥ 20) as follows:

P(X\geq 20)=1-P(X

Thus, the probability that at least 20 small aircraft arrive during a 2.5-hour period is 0.5298.

Compute the value of P (X ≤ 10) as follows:

P(X\leq 10)=\sum\limits^{10}_{x=0}(\frac{e^{-20}(20)^{x}}{x!})\\=0.01081\\\approx0.0108

Thus, the probability that at most 10 small aircraft arrive during a 2.5-hour period is 0.0108.

8 0
3 years ago
What is 8z - 22 = 3(3z + 11) - z
Masja [62]
8z-22=3(3z+11)-z
9z-22=9z+33
-22=33
or
0=55
either way no solution
6 0
3 years ago
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