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Grace [21]
3 years ago
13

The point (-6, y) lies on the graph of the equation: 5y=2x−4.

Mathematics
1 answer:
Vilka [71]3 years ago
7 0

Answer:

The answer is -16/5

Step-by-step explanation:


You might be interested in
The probability that a randomly chosen person has a dog is 0.34. The probability that a randomly chosen person will have a dog a
Elina [12.6K]

Taking into definition of probability, the probability that a randomly chosen person is not walking in the park is 0.91.

<h3>Definition of Probabitity</h3>

Probability is the possibility that a phenomenon or an event will happen, given certain circumstances. It is expressed as a percentage.

<h3>Union of events</h3>

The union of events, AUB, is the event formed by all the elements of A and B. That is, the event AUB is verified when one of the two, A or B, or both occurs. AUB is read as "A or B".

The probability of the union of two compatible events is calculated as the sum of their probabilities subtracting the probability of their intersection:

P(A∪B)= P(A) + P(B) -P(A∩B)

<h3>Complementary event</h3>

A complementary event is made up of the inverse of the results of another event. That is, That is, given an event A, a complementary event is verified as long as the event A is not verified.

The probability of occurrence of the complementary event A' will be:

P(A´)= 1- P(A)

<h3>Events and probability in this case</h3>

In first place, let's define the following events:

  • D: a person has a dog.
  • W: a person is walking in the park.

Then you know:

  • P(D)= 0.34
  • P(D and W)= P(D∩W)= 0.03 [The intersection of events, A ∩ B, is the event formed by all the elements that are, at the same time, from A and B. That is, the event A ∩ B is verified when A and B occur simultaneously.]
  • P(D or W)= P(D∪W)= 0.40

In this case, considering the definition of union of eventes, the probability that a randomly chosen person is walking in the park is calculated as:

P(D∪W)= P(D) + P(W) -P(D∩W)

0.40= 0.34 + P(W) -0.03

Solving:

0.40= 0.31 + P(W)

0.40 - 0.31= P(W)

<u><em>0.09= P(W)</em></u>

Then, the probability that a randomly chosen person is walking in the park is 0.09.

Considering the definition of the complementary event and its probability, the probability that a randomly chosen person is NOT walking in the park is calculated as:

P [W']= 1- P(W)

Replacing and solving:

P [W']= 1 - 0.09

P [W']= 0.91

Finally, the probability that a randomly chosen person is not walking in the park is 0.91.

Learn more about probability:

brainly.com/question/25839839

brainly.com/question/26038361

#SPJ1

7 0
2 years ago
help me please i got the answer which is 2 but how do i do the sqrt 3 part in the bottom in gold letters
Allisa [31]

|MN| =\sqrt{(x_{M}-x_{N})^{2}+(y_{M} - y_{N})^{2}} =\sqrt{(-6-(-1))^{2}+(-1-(-7))^{2}} = \\ \\ =\sqrt{25 +36} =\sqrt{61}  \\ \\Answer \ is \  \sqrt{61} .

4 0
3 years ago
Somebody pls help me with this
Sveta_85 [38]
Your answer is 3/16 I think this is accurate for the problem
5 0
4 years ago
2. Rectangle A has length 12 and width 8. Rectangle B has length 15 and width 10.
Katarina [22]

Answer:

Rectangle B is a scaled copy of rectangle A.

Enlargement scale factor = 1.25

Step-by-step explanation:

<u>Rectangle A:</u>

Length = 12 units

Width = 8 units

<u>Rectangle B:</u>

Length = 15 units

Width = 10 units

<u>Rectangle C:</u>

Length = 30 units

Width = 15 units

Rectangle B length ÷ rectangle A length = rectangle B width ÷ rectangle A width = 1.25

i.e \frac{15}{12} = \frac{10}{8} = 1.25

Hence rectangle B is a scaled copy of rectangle A and the scale factor of enlargement is 1.25

3 0
3 years ago
Read 2 more answers
The boys' basketball team at Washington High School has been doing really well so far this year. In the past six games, they've
Fofino [41]

The least likely measure of central tendency to be used would be; The range.

<h3>How to identify measures of central tendency?</h3>

We are given the points scored by the basketball team as;

84, 67, 74, 87, 67, 73

Now, the three major measures of central tendency are mean, median and mode.

Mean is the average while mode is the most frequent item while median is the middle term when arranged in ascending order.

However, when discussing their year, what the paper would like to know is their average amount of points per game for the year and as such he will use the mean.

However, the least likely measure of central tendency to be used would be the range.

Read more about Measures of central tendency at; brainly.com/question/17631693

#SPJ1

7 0
3 years ago
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