Find the quotient of the following:<br> (12x^4- 3x^4+ 15x^2)<br> and (

Donald has x twenty-dollar bills and 1 ten-dollar bill.<br> How much money does Donald have?

soldi70 [24.7K]

Answer:

10 +(20x)

Step-by-step explanation:

Donald has number of twenty-dollar bills = x

He has ten-dollar bill = 1

Total amount of bills = 10 +(20x)

The amount of the bill that Donald have is 10 + (20x)

4 0

3 years ago

Find the product (3x+8)(x-4)

timurjin [86]

Answer:

3 $x^{2}$ - 4x - 32

Step-by-step explanation:

(3x+8)(x-4)

=3 $x^{2}$ -12x + 8x -32

=3 $x^{2}$ - 4x - 32

7 0

3 years ago

Read 2 more answers

For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains

AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

There is an 85.5% probability that a drought lasts at most 3 intervals.

b)There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

$f(x) = (1-p)^{x}p$

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

$\mu = \frac{1-p}{p}$

The standard deviation of the geometric distribution is given by the following formula:

$\sigma = \sqrt{\frac{1-p}{p^{2}}$

In this problem, we have that:

$p = 0.383$

So

$\mu = \frac{1-p}{p} = \frac{1-0.383}{0.383} = 1.61$

$\sigma = \sqrt{\frac{1-p}{p^{2}}} = \sqrt{\frac{1-0.383}{(0.383)^{2}}} = 2.05$

(a) What is the probability that a drought lasts exactly 3 intervals?

This is $f(3)$

$f(x) = (1-p)^{x}p$

$f(3) = (1-0.383)^{3}*(0.383)$

$f(3) = 0.09$

There is a 9% probability that a drought lasts exactly 3 intervals.

At most 3 intervals?

This is $P = f(0) + f(1) + f(2) + f(3)$

$f(x) = (1-p)^{x}p$

$f(0) = (1-0.383)^{0}*(0.383) = 0.383$

$f(1) = (1-0.383)^{1}*(0.383) = 0.236$

$f(2) = (1-0.383)^{2}*(0.383) = 0.146$

Previously in this exercise, we found that $f(3) = 0.09$

So

$P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855$

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is $P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4)$ .

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

$P(X \leq 3) + P(X \geq 4) = 1$

$0.855 + P(X \geq 4) = 1$

$P(X \geq 4) = 0.145$

There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

8 0

3 years ago

[Help Asap, Will Mark Brainliest] Answer is in the image,

Vera_Pavlovna [14]

Z=118 as vertically opposite angles are the same

x= (8x-50)

3 0

3 years ago

Read 2 more answers

State whether the following statement is true or false, and explain why. If the statement is false, state the true change. A h

katovenus [111]

Answer:

False

Step-by-step explanation:

Given that a high school reports that its students' SAT scores were down by 12% in one year. The next year, however, the test scores rose by 20%.

Let score initially be 100

Down by 12

Next year score 88

For succeedingyear

increase is 20% = $20% of 88=17.6\\$

Score in the 2nd year = $88+17.6 = 105.6$

Hence overall scores improvement is 5.6% and not 8%

5 0

2 years ago

Find the quotient of the following: (12x^4- 3x^4+ 15x^2) and ( - 3x)