Find the quotient of the following:<br> (12x^4- 3x^4+ 15x^2)<br> and (

D is between C and E, CD = x 2 , CE = 32-2x, and DE = 12x. Find CD, DE, and CE.

Gemiola [76]

Answer:

CD = 4
DE = 24
CE = 28

Step-by-step explanation:

The segment addition theorem tells you ...

CD +DE = CE

x^2 +12x = 32 -2x

Subtract the right side to put this in standard form.

x^2 +14x -32 = 0

(x +16)(x -2) = 0

x = -16 or 2

In order for DE to have a positive length, we must have x > 0. So ...

CD = x^2 = 2^2 = 4

DE = 12x = 12(2) = 24

CE = 32 -2x = 32 -2(2) = 28

3 0

3 years ago

Simplify (Cot t) (Sin t)/(Cos t)

Serhud [2]

Answer:

1

Step-by-step explanation:

(Cot t) (Sin t)/(Cos t)

cot = cos / sin

Replacing cot t with cos t / sin t

cos t/ sin t * (Sin t)/(Cos t)

Canceling the sin t's

cos t / cos t

1

7 0

3 years ago

I need help i don’t know this at all

alexgriva [62]

Answer:

Step-by-step explanation:

Yes what is the problemo! :>

5 0

3 years ago

Please, help!!!! Bussines Calc. I give 20 points. I need a full explanation.

maksim [4K]

Answer:

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Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Please Help! I can’t figure this question out! Question is in the pic below..

padilas [110]

The answer is 68!!!!!!!!!

4 0

2 years ago

Find the quotient of the following: (12x^4- 3x^4+ 15x^2) and ( - 3x)