59 is a prime number, so no two intergers can multiply together to make it.
Simple...
you have:
![4 \frac{4}{9}](https://tex.z-dn.net/?f=4%20%5Cfrac%7B4%7D%7B9%7D%20)
To make this into an improper fraction-->>
1.) Multiply whole number by denominator
2.)Add the number you got plus the numerator
3.) Use the original denominator to finish your improper fraction
Example:
![4\frac{4}{9}](https://tex.z-dn.net/?f=%204%5Cfrac%7B4%7D%7B9%7D%20)
4*9=36
36+4=40
![\frac{40}{9}](https://tex.z-dn.net/?f=%20%5Cfrac%7B40%7D%7B9%7D%20)
Thus, your answer.
Ummm I think b orrr A good luck!
I'm not 100% sure what you're asking, but i think it wants:
50,000 + 25,000 = 75,000 - so B is the answer
to do it you basically just round the number to the nearest 1000 and add
No, it's always okay to ask if you don't understand a question. Anyway, for this problem, we just have to plug in the value for <em>V </em>to solve for <em>P</em> :
![P = 4V^{ \frac{1}{3}} \\ P = 4(125)^{ \frac{1}{3}}](https://tex.z-dn.net/?f=P%20%3D%204V%5E%7B%20%5Cfrac%7B1%7D%7B3%7D%7D%20%5C%5C%20P%20%3D%204%28125%29%5E%7B%20%5Cfrac%7B1%7D%7B3%7D%7D)
A number to the power of 1/3 is the same as taking a cube root.
![P = 4(125)^{ \frac{1}{3}} \\ P = 4(5) \\ P=20](https://tex.z-dn.net/?f=P%20%3D%204%28125%29%5E%7B%20%5Cfrac%7B1%7D%7B3%7D%7D%20%5C%5C%20P%20%3D%204%285%29%20%5C%5C%20P%3D20)
The perimeter of one face of the cube is 20m.