[(8 - 2 * 29)]/3
Let's solve inside the brackets first.
According to PEMDAS, multiplication gets solved before subtraction so multiply 2 * 29 in the parentheses.
[(8 - 58)]/3
Subtract 58 from 8 in the parentheses.
(-50)/3
Divide -50 by 3.
-16.667 or -16 2/3 is your answer.
The answer would have to be like the same as the first day, so that being said you would have to add. I think the answer is 2,2,4. hope this helps.
To find the GCF first list down the prime factors of each number then multiply the factors both have in common, or if the numbers have only one prime factor in common then that's the answer. to find the prime factors of a number just divide the number by prime factors in order.
in this question prime factors of the numbers are,
18=2×2×3
45=3×3×3
90=2×3×3×5
the common factors are 3 and 3. so now multiply 3 by 3= 9
answer=9
hope this helps....
Answer:
0.6065
Step-by-step explanation:
Probability mass function of probability distribution : 
a mean of 0.05 flaw per square foot
Each car contains 10 sq.feet of the plastic roll
Mean = 0.05
Mean =
We are supposed to find What is the probability that there are no flaws in a given car’s interior i.e,P(X=0)
Substitute the value in the formula



Hence the probability that there are no flaws in a given car’s interior is 0.6065
Answer:
13 units
Step-by-step explanation:
(x₁,y₁) = (-5 , 3) & (x₂ , y₂) = (7 ,8)

![= \sqrt{(7-[-5])^{2}+(8-3)^{2}} \\\\= \sqrt{(7+5)^{2}+(8-3)^{2}} \\\\= \sqrt{(12)^{2}+(5)^{2}}\\\\=\sqrt{144+25}\\\\=\sqrt{169}\\\\= 13](https://tex.z-dn.net/?f=%3D%20%5Csqrt%7B%287-%5B-5%5D%29%5E%7B2%7D%2B%288-3%29%5E%7B2%7D%7D%20%5C%5C%5C%5C%3D%20%5Csqrt%7B%287%2B5%29%5E%7B2%7D%2B%288-3%29%5E%7B2%7D%7D%20%5C%5C%5C%5C%3D%20%20%5Csqrt%7B%2812%29%5E%7B2%7D%2B%285%29%5E%7B2%7D%7D%5C%5C%5C%5C%3D%5Csqrt%7B144%2B25%7D%5C%5C%5C%5C%3D%5Csqrt%7B169%7D%5C%5C%5C%5C%3D%2013)