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ddd [48]
3 years ago
14

Anna is moving and must rent a truck. In addition to an initial fee, the rental company charges a fee of $3 per mile driven. If

Anna were to drive 5 miles, the total cost would be $50. Write an equation for C,C, in terms of m,m, representing the total cost of renting the truck if Anna were to drive mm miles.
Mathematics
1 answer:
Scilla [17]3 years ago
6 0

Answer: 3m+35

Step-by-step explanation:

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Which of these polynomial equations is of least degree and has -1, 2, and 4 as three of its roots?
kvasek [131]

Answer:

x^3 - 5 x^2 + 2 x + 8 = 0

Step-by-step explanation:

Solve for x over the real numbers:

x^3 - 5 x^2 + 2 x + 8 = 0

The left hand side factors into a product with three terms:

(x - 4) (x - 2) (x + 1) = 0

Split into three equations:

x - 4 = 0 or x - 2 = 0 or x + 1 = 0

Add 4 to both sides:

x = 4 or x - 2 = 0 or x + 1 = 0

Add 2 to both sides:

x = 4 or x = 2 or x + 1 = 0

Subtract 1 from both sides:

Answer: x = 4 or x = 2 or x = -1

6 0
3 years ago
Read 2 more answers
If 235=19,432 than248=?
GrogVix [38]
Hey there!

The answer for your problem is: 248=20,507 (rounded)

Let me know if you'd like me to explain how I got this answer!
7 0
3 years ago
Give the digits in the tens place and the hundredths place.<br> 59.78<br> tens:<br> hundredths:
Roman55 [17]
Tens: 59

Hundredths: 78

Please give brainliest
4 0
2 years ago
From a shipment of 65 transistors, 6 of which are defective, a sample of 5 transistors is selected at random.
Vladimir79 [104]

Answer:

a) 8259888

b) 34220

c) 45057474

Step-by-step explanation:

Given,

The total number of transistor = 65,

In which, the defective transistor = 6,

So, the number of non defective transistor = 65 - 6 = 59,

Since, out of these transistor 5 are selected,

a) Thus, the number of ways = the total possible combination of 5 transistors = {65}C_ 5

=\frac{65!}{(65-5)!5!}

=8259888

b) The number of samples that contains exactly 3 defective transistors = the possible combination of exactly 3 defective transistors = {6}C_3\times {59}C_2

=\frac{6!}{(6-3)!3!}\times \frac{59!}{(59-2)!\times 2!}

=20\times 1711

=34220

c) The number of sample without any defective transistor = The possible combination of 0 defective transistor = ^6C_0\times ^{59}C_5

=1\times 45057474

=45057474

5 0
3 years ago
If a system of linear equations has one solution, what does this mean about the two lines?
MariettaO [177]

Answer:

It means two lines intersected.

C is correct

Hope this helps!

:)

5 0
3 years ago
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