Answer:
Length = 50 feet
Width = 160 feet
Explanation:
I'm assuming the flagpole is not included in this question.
w
=
w
i
d
t
h
l
=
≤
n
>
h
The length compared to the width is:
w
=
l
+
110
<-- equation 1
The formula for perimeter:
P
=
2
w
+
2
l
420
=
2
w
+
2
l
<-- equation 2
Sub the first equation into the second.
420
=
2
(
l
+
110
)
+
2
l
Now you can solve for
l
algebraically.
420
=
2
l
+
220
+
2
l
4
l
=
200
l
=
50
Sub the found length into the first equation to find the length.
w
=
(
50
)
+
110
w
=
160
Therefore the flag is 50 feet long and 160 feet wide.
Answer:
20*(20+1)/2 = 210
Step-by-step explanation:
Answer:
Step-by-step explanation:
Used PEMDAS:
P Parentheses first
E Exponents (ie Powers and Square Roots, etc.)
MD Multiplication and Division (left-to-right)
AS Addition and Subtraction (left-to-right)
First Power, next Addition
Answer:
Step-by-step explanation:
it's even because f(-x)=f(x)
Answer:
P = -12xy - 56y - 42x + 8
Step-by-step explanation:
P = 2L + 2W
P = 2(4 - 7(3x + 4y)) + 2(3x(-2y))
P = 8 - 14(3x + 4y) + 6x(-2y)
P = 8 - 42x - 56y - 12xy
P = -12xy - 56y - 42x + 8
