I think the answers are A, C, A.
The reason why Br has a greater magnitude of electron affinity than that of I is that there is a greater attraction between an added electron and the nucleus in Br than in I.
In the periodic table, there are trends that increase down the group and across the period. Electron affinity is a trend that increases across the period but decreases down the group.
Recall that the ability of an atom to accept an electron depends on the size of the atom. The smaller the atom, the greater the attraction between an added electron and the nucleus.
Since Br is smaller than I, there is a greater attraction between an added electron and the nucleus in Br than in I which explains why Br has a greater magnitude of electron affinity than I.
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Answer:
it increases and is perpendicular to the motion of the wave.
Answer:
Equilibrium constant Kc = Qc = quotient of reactant(s) and product(s)
Kc = [C]x[D]y..../[A]m[B]n..... = 0.328dm3/mol, where [C]x[D]y is the product and [A]m[B]n is the reactant(Both in gaseous states)
Explanation:
When a mixture of reactants and products of a reaction reaches equilibrium at a given temperature, its reaction quotient always has the same value. This value is called the equilibrium constant (K) of the reaction at that temperature. As for the reaction quotient, when evaluated in terms of concentrations, it is noted as Kc.
That a reaction quotient always assumes the same value at equilibrium can be expressed as:
Qc (at equilibrium) = Kc =[C]x[D]y…/[A]m[B]n…
This equation is a mathematical statement of the law of mass action: When a reaction has attained equilibrium at a given temperature, the reaction quotient for the reaction always has the same value.
Answer:
The above compound is an ether. Give thestructure of the product(s) and indicate the major mechanism of the reaction (SN1, SN2, E1 or E2). Indicate stereochemistry when necessary.
The mechanism that explains this transformation begins with the protonation of the ether, which allows the subsequent SN2 attack of the iodide ion. This reaction forms ethyl iodide and ethanol, which is also converted to ethyl iodide by reaction with excess HI.
Explanation:
The SN2 reaction (also known as bimolecular nucleophilic substitution or as an attack from the front) is a type of nucleophilic substitution, where a pair of free electrons from a nucleophile attacks an electrophilic center and binds to it, expelling another group called the leaving group. Consequently, the incoming group replaces the outgoing group in one stage. Since the two reactant species are involved in this slow limiting stage of the chemical reaction, this leads to the name bimolecular nucleophilic substitution, or SN2. Among inorganic chemicals, the SN2 reaction is often known as the exchange mechanism.
