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k0ka [10]
2 years ago
10

Can you please help me (50 points)

Chemistry
1 answer:
Anna35 [415]2 years ago
4 0

Answer:

P=15

N=59

Explanation:

Pic is blurry but I based my answer on bottom number being 74

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Convert 533 cm/s to units of meters per minute. Show the unit analysis by dragging the conversion factors into the unit‑factor s
lukranit [14]

Answer:

319.8 m/min

Explanation:

533 cm/s

We can convert 533 cm/s to m/min by doing the following:

First, we shall convert 533 cm/s to m/s. This can be obtained as illustrated below:

Recall:

100 cm/s = 1 m/s

Therefore,

533 cm/s = 533 cm/s /100 cm/s × 1 m/s

533 cm/s = 5.33 m/s

Finally, we shall convert 5.33 m/s to m/min. This can be obtained as follow:

1 m/s = 60 m/min

Therefore,

5.33 m/s = 5.33 m/s / 1 m/s × 60 m/min

5.33 m/s = 319.8 m/min

Therefore, 533 cm/s is equivalent to 319.8 m/min

8 0
3 years ago
Can you think of any practical reasons why you might want to know if there is carbon dioxide in air mixtures? please help
san4es73 [151]
Yes.  carbon dioxide is deadly and i want to get away from it fast.
8 0
3 years ago
Help?
pashok25 [27]
I think it’s B, D, E
7 0
2 years ago
What can you infer about the volume of a gas as absolute zero is approached?
schepotkina [342]

Answer:

The volume of a gas approaches zero as the temperature approaches absolute zero.

Step-by-step explanation:

You may have done a <em>Charles' Law experiment</em> in the lab, in which you measured the volumes of a gas at various temperatures.

You plotted them on a graph, and perhaps you were asked to extrapolate the graph to lower temperatures.

Your graph probably looked something like the one below.

There is clearly an x-intercept at some low temperature.

Inference: The volume of a gas approaches zero as the temperature approaches absolute zero.

4 0
2 years ago
Consider the reaction between iron (III) oxide, Fe2O3 and carbon monoxide, CO.
Lana71 [14]
<span>Fe2O3 + 3CO --> 2Fe + 3CO2
</span><span>
m(Fe2O3)=213 g
m(CO)=140 g
</span>_______________

<span>n(Fe2O3)=?
m(Fe)=?
n(Fe2O3)=?
n(CO)=?
n(CO2)=?
</span>
<span>n(Fe2O3)=m(Fe2O3) / M(Fe2O3)
n(Fe2O3)= 213 g / 159,7 gmol-1 = 1,33 mol
</span>
<span>n(CO)= m(CO) / M(CO) n(CO)= 140 g / 28,01 gmol-1 = 4,99 mol</span>
3 0
3 years ago
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