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2 years ago

Help plez this was due yesterday

Chemistry

1 answer:

Anna11 [10]2 years ago

5 0

Prokaryotic cells are unicellular
Eukaryotic cells are multicellular
Plant and animal cells are prokaryotic and eukaryotic because ↓
Prokaryotic cells- plants cells
Eukaryotic cells- animals cells
I am pretty sure that prokaryotic and eukaryotic cells are considered to be living due to the cell theory because the cell theory states that all living things are made of cells.

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To draw the Lewis structure of the polyatomic ion,CIO3 you would have to _____ those in the structures of Cl, O, O, and O. Selec

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D. Add one electron to,

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3 years ago

1. If you were working for a beverage company, which molarity would you recommend, and what directions for mixing would you crea

emmasim [6.3K]

Answer: I would prepare a standard solution

Explanation: A standard solution is a solution of known concentration (molarity). This is gotten from the stock using dilution principle. (C1V1=C2V2) I would prepare a 0.1M solution of the beverage into a standard 500ml flask.

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2 years ago

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3 years ago

Using the following thermochemical equation, determine the amount of heat produced per kg of CO2 formed during the combustion of

Arisa [49]

Answer: 12033 kJ of heat produced per kg of $CO_2$ formed during the combustion of benzene

Explanation:

The balanced chemical equation for combustion of benzene is :

$2C_6H_6(l)+15O_2(g)\rightarrow 12CO_2(g)+6H_2O(g)$ $\Delta H°rxn$ = -6278 kJ

Exothermic reactions are defined as the reactions in which energy of the product is lesser than the energy of the reactants. The total energy is released in the form of heat and $\Delta H$ for the reaction comes out to be negative.

$\text{Moles of }CO_2=\frac{\text{given mass}}{\text{Molar Mass}}=\frac{1000g}{44g/mol}=23mol$ (1kg=1000g)

According to stoichiometry :

12 moles of $CO_2$ on combustion produce heat = 6278 kJ

Thus 23 mole of $CO_2$ on combustion produce heat = $\frac{6278}{12}\times 23=12033kJ$

Thus 12033 kJ of heat produced per kg of $CO_2$ formed during the combustion of benzene

5 0

2 years ago

Consider this mechanism:

DerKrebs [107]

Answer:

$ClO^- + I^-\rightarrow IO^- + Cl^-$

Explanation:

Given a reaction mechanism, we will typically have catalysts and intermediates which will not be observed in the final balanced overall reaction. In order to obtain a net reaction, we need to add all the separate steps of the given reaction.

First of all, the reactants are combined followed by a combination of products. The repeating species on both sides of the final equation are then canceled out. Let's sum everything we have in our steps:

$ClO^- + H_2O + I^- + HClO + OH^- + HIO\rightarrow HClO + OH^- + HIO + Cl^- + H_2O + IO^-$

Repeating species that can be canceled out are:

$H_2O,~HClO,~OH^-,~HIO$

This leaves a net reaction of:

$ClO^- + I^-\rightarrow IO^- + Cl^-$

5 0

2 years ago