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Monica [59]
3 years ago
7

What isotope remains after the alpha decau of uranium-238?

Chemistry
1 answer:
lbvjy [14]3 years ago
4 0
After alpha decay (234,90) remain from it
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The kind of energy released when atoms are rearranged to form new bond
Murljashka [212]
The kind of energy released when atoms are rearranged to form new bonds is called Chemical energy.
6 0
3 years ago
Give three properties of a Solid
NARA [144]
In a solid, molecules are packed together, and it keeps its shape. Liquids take the shape of the container. Gases spread out to fill the container. Solid is one of the three main states of matter, along with liquid and gas.

Hope that helps!
8 0
3 years ago
How many moles of sodium phosphate would be required to react with 1.0 mol of silver nitrate
WITCHER [35]
1) State the balanced chemical equation

Na3 PO4                  + 3 AgNO3        → 3NaNO3        +        Ag3 PO4

sodium phosphate        silver nitrate       sodium nitrate    silver phosphate

2) State the molar ratios

1 mol Na3PO4 : 3 mol AgNO3 : 3 mol NaNO3 : 1 mol Ag3 PO4

3) As you see 3 moles of Silver Nitrate react with 1 mol of Na3 PO4, then you will need.

The you need to use the molar ratio 1:3 to calculate the number of moles of sodium phosphate

1 mol Ag NO3 * [ 1 mol Na3 PO4 / 3 mol Ag NO3] = 0.33 mol Na3 PO4

Answer: 0.33 mol sodium phosphate
3 0
4 years ago
Calculate the mass of glucose metabolized by a 60.0 −kg person in climbing a mountain with an elevation gain of 1550 m . Assume
lbvjy [14]

Answer:

Mass of glucose = 515.34 g

Explanation:

We are given;

Mass; m = 60 kg

Elevation; h = 1550 m

Acceleration due to gravity; 9.8 m/s²

Now, work performed to lift 60kg by 1550m is given by the formula;

W = mgh

W = 60 × 9.8 × 1550

W = 911400 J

We are told the actual work is 4 times the one above.

Thus;

Actual work = 4W = 4 × 911400 = 3,645,600 J

Now,

Molar mass of Glucose(C6H12O6) = 180 g/mol

We are given standard enthalpy of combustion = -1273.3 KJ/mol = -1273300

Moles of glucose = 3645600/1273300 = 2.863mol

Mass of glucose = 2.863 mol × 180 g/mol

Mass of glucose = 515.34 g

4 0
4 years ago
2. How many kilometers are in 8432 meters?
Delicious77 [7]

Answer:

8.432 Kilometers

Explanation:

This is the answer because 1 kilometer equals to 1,000 meters:

1) Divide 8432 with 1,000

2) Once you divide, you will get 8.432 as your answer

Hope this helps!

3 0
3 years ago
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