Answer:
5x^2+x-6
Step-by-step explanation:
(5x-1)(x+1)-5x+x-5+x
(5x^2+5x-x-1)-5x+x-5+x
5x^2+x-6
Miranda is correct. 30×26=780 and 20×36=720 so 30×26>20×36
The size of angle PRQ is 15°
Step-by-step explanation:
In any regular polygon of n-sided
- All sides are equal in length
- All angles are equal in measure
- The measure of each interior angle is

- The measure of each exterior angle is

- The sum of the measures of the interior and exterior angle at the same vertex is 180°
∵ PQ and QR are two sides of a regular 12-sided polygon
∴ PQ = QR
∵ PR is a diagonal
∴ ∠PQR is an interior angle of the polygon
- By using the rule of the interior angle above
∵ n = 12
∴ m∠PQR = 
∴ m∠PQR = 150°
In Δ PQR
∵ PQ = QR ⇒ sides in a regular polygon
- Δ PQR is an isosceles Δ
∴ m∠PRQ = m∠RPQ ⇒ base angles of an isosceles Δ
The sum of the measures of the interior angles of a triangle is 180°
∵ m∠PQR + m∠PRQ + m∠RPQ = 180°
∴ 150 + m∠PRQ + m∠RPQ = 180°
- Subtract 150 from both sides
∴ m∠PRQ + m∠RPQ = 30
∵ m∠PRQ = m∠RPQ
- Divide their sum by 2 to find the measure of each one
∴ m∠PRQ = m∠RPQ = 30 ÷ 2 = 15°
∴ m∠PRQ = 15°
The size of angle PRQ is 15°
Learn more:
You can learn more about the triangles in brainly.com/question/3945600
#LearnwithBrainly
We know that In right angle triangle c^2 = a^2 + b^2.
19^2 = 3^2 + b^2
b = (361 - 9)^1/2 = 18.761663039294
Now for angles
sin(A) = a/c = 3/19
A = sin{-1}(3/19) = 9.0847202873911
A = 9.0847202873911
sin(B) = b/c = 18.761663039294 / 19
B = sin{-1}(18.761663039294 / 19) = 80.915279712614
B = 80.915279712614
Answer:
B. 4 imaginary; 1 real
Step-by-step explanation:
Given the polynomial:
x^5 + 7*x^4 + 2*x^3 + 14*x^2 + x + 7
it can be reordered as follows
(x^5 + 2*x^3 + x ) + (7*x^4 + 14*x^2 + 7)
Taking greatest common factor at each parenthesis
x*(x^4 + 2*x^2 + 1) + 7*(x^4 + 2*x^2 + 1)
Taking again the greatest common factor
(x + 7)*(x^4 + 2*x^2 + 1)
Replacing x^2 = y in the second parenthesis
(x + 7)*(y^2 + 2*y + 1)
(x + 7)*(y + 1)^2
Coming back to x variable
(x + 7)*(x^2 + 1)^2
There are two options to find the roots
(x + 7) = 0
or
(x^2 + 1)^2 = 0 which is the same that (x^2 + 1) = 0
In the former case, x = -7 is the real root. In the latter, (x^2 + 1) = 0 has no real solution. Therefore, there is only 1 real root in the polynomial.