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cluponka [151]
4 years ago
5

A firework is ignited, and explodes with a flash and a loud bang as it is blown apart. The system consists of: the firework, the

Earth, and the air.
Which choice best describes how energy is transformed in the system?
Physics
1 answer:
butalik [34]4 years ago
8 0

The complete question is:

Study the scenario. A firework is ignited, and explodes with a flash and a loud bang as it is blown apart. The system consists of: the firework, the earth, and the air. which choice best describes how energy is transformed in the system?

A) When the firework is ignited, a chemical reaction absorbs energy from the surrounding environment. the energy is in several forms including sound and light, and mechanical energy of the fragments of the firecracker that are launched through the air. Eventually all the energy released is transformed into thermal energy.

B) When the firework is ignited, a chemical reaction releases energy in several forms, including sound, light, and the mechanical energy of the fragments being launched through the air. Eventually all the energy released is transformed into mechanical energy.

C) When the firework is ignited, a chemical reaction releases energy in several forms, including sound, light, and the mechanical energy of the fragments being launched through the air. Eventually all the energy released is transformed into thermal or mechanical energy.

D) When the firework is ignited, a chemical reaction absorbs energy from the surrounding environment. The energy is taken in in several forms including sound and light, and mechanical energy of the fragments being launched through the air. Eventually all the energy is transformed into thermal energy.

Answer:

C) When the firework is ignited, a chemical reaction releases energy in several forms, including sound, light, and the mechanical energy of the fragments being launched through the air. Eventually all the energy released is transformed into thermal or mechanical energy.

Explanation:

Energy is released from the system, not absorbed.

All the sound, light and movement of the debris is as a result of energy transformation from the chemical energy.

Eventually, most of the energy are finally wasted away as heat energy.

Some of the energy is used up by the flying particles from the fireworks.

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Would you buy a pair of shoes from the same company that sold Jack his shoes? Why or why not?
LenKa [72]

Answer:

Maybe

Explanation:

It depends. If he says the shoes sucked than no because they suck-

But if he really liked the shoes and said it was really good than yes

I would buy the shoes

8 0
3 years ago
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A cart with mass 2.0 kg moving on a frictionless linear air track at an initial speed of 1.0 m/s undergoes an elastic collision
Katen [24]

Answer:

a) P=0.8 Kg*m/s b) K=0.6 N c)P/K=MV/(1/2*MV²) d) V2f=1.5 m/s e) M2=0.53 Kg

Explanation:

During an elastic collision between 2 bodies, the momentum P is the same before and after the collision

For this case:

Before the collision:

M₁= mass of first car= 2 Kg

V₁= initial speed of the first car = 1 m/s

M₂= mass of the second car

V₂= initial speed of the second car = 0 m/s (as it is stationary)

After the collision:

V₁f= final speed of the first car after the collision= 0.6 m/s

V₂f= final speed of the second car after the collision

As momentum is the same after and before:

M₁V₁ + M₂V₂ = M₁V₁f + M₂V₂f consider that term M₂V₂=0 as V₂=0

Then, momentum for car N° 2 after the collision is: P₂= M₂V₂f and replacing from the above equation: P₂= M₁V₁ – M₁V₁f = M₁(V₁ – V₁f) = 2 Kg*(1m/s – 0.6m/s) = 0.8 Kg*m/s

As the kinetic energy “K” is also conservative:

½*M₁V₁² + ½*M₂V₂² = ½*M₁V₂f² + ½*M₂V₂f² Where ½*M₂V₂²=0

Then: K₂= ½*M₂V₂f² = ½*M₁(V₁² – V₁f²) = 0.64 N

Finally, to obtain M₂ and V₂f:

P₂=M₂V₂f and K₂=1/2*M₂V₂f2²

P₂/K₂= (M₂V₂f)/(1/2*M₂V₂f) =2/V₂f  

V₂f= 2*K₂/P₂=1.5 m/s and M₂=P₂/V₂f=0.53 Kg

8 0
3 years ago
Standing on top of a building, Bob tosses a baseball straight up with an initial speed of 15 m/s. It takes 4.0 s for the ball to
r-ruslan [8.4K]

Answer:

48.26 m

Explanation:

time to goes up (till stop for a while in the air - maximum height)

vt = vo + a t

0 = 15 + g . t

0 = 15 + (-9.8) . t

9.8t = 15

t = 1.531 s

so the time left to goes down is

4.0 - 1.531 = 2.469 s

height from the top of building can find it by using

vo =√(2gh)

15 = √(2)(9.8).h

15² = 19.6h

h = 225/19.6 = 11.48 m

so the distance of maximum height to the ground is

t = √(2H/g)

2.469 = √(2H/9.8)

2.469² = 2H/9.8

6.096 = 2H/9.8

2H = 6.096 x 9.8 = 59.74 m

so the vertical distance of the building (or the building height's is)

H - h = 59.74 - 11.48 = 48.26 m

5 0
3 years ago
A shell traveling with speed, v0 , exactly horizontally and due north explodes into two equal mass fragments. It is observed tha
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Answer:

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Explanation:

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How much force is needed to accelerate a 68 kilogram-skier at a rate of 1.2 m/sec^2?
DiKsa [7]
<span>Answer: Force = 81.6 N

Explanation:
According to Newton's Second law:
F = ma --- (1)

Where F = Force = ?
m = Mass = 68 kg
a = Acceleration = 1.2 m/s^2

Plug in the values in (1):
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F = 81.6 N (The force needed to accelerate the skier at a rate of 1.2 m/s^2)</span>
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3 years ago
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