1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
klemol [59]
3 years ago
10

7.

Physics
2 answers:
SSSSS [86.1K]3 years ago
7 0

Free fall is a special type of motion in which the gravity is the only force that acting upon an object.

<u>Explanation</u>:

In the free fall the object have gravity force only. when you dropped the ball from top of the building, and it will start falling. The balls falls due to gravity. Imagine when you have held the ball in your hand, gravity is acting, but the frictional force between your fingers and ball is acting on the opposite side. When the ball is kept in air, gravity is the only force that acts on the ball. Hence in free fall, the object has no another forces except gravity.

Igoryamba3 years ago
5 0

D. Free fall

Explanation:

An object is said to be in free fall when there is only one force acting on the body, which is the force of gravity.

Near the Earth's surface, the force of gravity acting on a body is given by

F = mg

where

m is the mass of the body

g is the acceleration of gravity (its value is 9.8 m/s^2)

The direction of this force is downward (towards the Earth's centre).

If we apply Newton's second law on an object in free-fall, we can find its acceleration. In fact, we have:

a=\frac{F}{m}

And substituting F,

a=\frac{mg}{m}=g=9.8 m/s^2

So, every object in free-fall accelerates at 9.8 m/s^2 towards the ground.

Learn more about free fall here:

brainly.com/question/1748290

brainly.com/question/11042118

brainly.com/question/2455974

brainly.com/question/2607086

#LearnwithBrainly

You might be interested in
For the image of the overhead projector to be in focus, the distance from the projector lens to the image, <img src="https://tex
rjkz [21]
Given:
distance from the projector lens to the image, di
projector lens focal length, f
distance from the transparency to the projector lens, do

thin lens equation: 1/f = 1/di + 1/do
do = 4 inches
di = 8 feet

convert feet to inches, for uniformity.
1 foot = 12 inches
8 feet * 12 inches/ft = 96 inches
 
1/f = 1/96 inches + 1/4 inches

Adding fractions, denominator must be the same.

1/f = (1/96 * 1/1) + (1/4 * 24/24)
1/f = 1/96 + 24/96
1/f = 25/96

to find the value of f, do cross multiplication
1*96 = f * 25
96 = 25f
96/25 = f
3.84 = f

The focal length of the project lens is 3.84 inches 

4 0
3 years ago
Knowledge of projectile motion might help you aim a basketball when you throw it so it is more likely to go into the basket. tru
8_murik_8 [283]

Answer: True.

Explanation:

You would be able to visualize the basketballs height going up and when it sinks down into the hoop.

5 0
2 years ago
In certain cases, using both the momentum principle and energy principle to analyze a system is useful, as they each can reveal
kramer

Explanation:

The gravitational force equation is the following:

F_G = G * \frac{m_1 m_2}{r^2} \\

Where:

G = Gravitational constant = 6.67408 * 10^{-11} m^3 kg^{-1} s^{-2}

m1 & m2 = the mass of two related objects

r = distance between the two related objects

The problem gives you everything you need to plug into the formula, except for the gravitational constant. Let me know if you need further clarification.

8 0
3 years ago
An object with a mass of 0.5 kilometre start from rest and achieves a maximum speed of 20 metre per second in 0.01 second, what
Katarina [22]

Answer:

Hiii how are you <u>doing?</u><u>?</u><u>I </u><u>don't</u><u> </u><u>understand</u><u> </u><u>that</u>

3 0
2 years ago
A cat dozes on a stationary merry-go-round, at a radius of 4.4 m from the center of the ride. The operator turns on the ride and
monitta

Answer:

The coefficient of static friction is 0.29

Explanation:

Given that,

Radius of the merry-go-round, r = 4.4 m

The operator turns on the ride and brings it up to its proper turning rate of one complete rotation every 7.7 s.

We need to find the least coefficient of static friction between the cat and the merry-go-round that will allow the cat to stay in place, without sliding. For this the centripetal force is balanced by the frictional force.

\mu mg=\dfrac{mv^2}{r}

v is the speed of cat, v=\dfrac{2\pi r}{t}

\mu=\dfrac{4\pi^2r}{gt^2}\\\\\mu=\dfrac{4\pi^2\times 4.4}{9.8\times (7.7)^2}\\\\\mu=0.29

So, the least coefficient of static friction between the cat and the merry-go-round is 0.29.

4 0
3 years ago
Other questions:
  • Can someone solve this problem and explain to me how you got it​
    6·1 answer
  • Describe the motion of a skydiver from the time he jumps to the time he lands safely on the ground
    9·1 answer
  • Which of the following is not a name of a scale for measuring temperature? A. Kelvin B. Celsius C. Absolute D. Fahrenheit
    14·1 answer
  • what is is the ratio of the distance over which the force is applied to the distance over which the load is moved
    7·1 answer
  • Evangelista Torricelli was the first person to realize that we live at the bottom of an ocean of air. He correctly surmised that
    14·1 answer
  • What is wrong with the following statement: When you exert a force on a baseball, the equal and opposite force on the ball balan
    12·1 answer
  • Which would take longer to cool off by 50 degrees, 1 kg of Copper or 1 kg of liquid water?
    11·2 answers
  • 32. Increasing the amplitude of a sound wave produces a
    12·1 answer
  • How do mathematical models help us learn about conditions inside the sun?
    5·1 answer
  • The principles that you will examine in this lab can be illustrated by studying a falling bucket. Imagine a frictionless pulley
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!