3 years ago

Click the picture to se question

Physics

1 answer:

Gnesinka [82]3 years ago

5 0

The answer is F. slab pull, I think :)

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Factors that affect the force of gravity between objects include their distance apart and their

mr_godi [17]

Answer:

factors that affect the force of gravity between objects include their distance apart and their mass.

Explanation:

6 0

3 years ago

If the ball reaches the ground in 8 seconds and the velocity of the ball before it hits the ground is 78.4. What is its accelera

Natasha2012 [34]

Answer:

9.8 m / s^2

Explanation:

Assuming free fall====> there is no initial downward/upward velocity

Assuming metric units 78.4<u> m/s </u>

vf = a t

78.4 = a (8) shows a = 9.8 m/s^2

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2 years ago

When electrons are moving freely between many positive ions, what type of bond is occuring?

exis [7]

Answer:

a metallic

Explanation:

Metal atoms are joined together by metallic bonds. Metals can form cations (positive ions) with a sea of delocalized electrons.

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3 years ago

The speed of propagation of electrical signals in a nerve cell depends on the diameter of the axon (nerve fiber). If the nerve c

gayaneshka [121]

Answer:

61 ms

Explanation:

Given that

Length of the nerve call connecting the spinal cord to your feet, s is 1.1 m

Speed of the impulse of the nerve, v = 18 m/s

Time taken by the nerve to travel the distance, t = ?

In solving this, we'd apply the very most basic formula in physics. Formula of speed, with respect to time and distance.

Speed, v = distance, s / time, t

time, t = distance, s / speed, v

time, t = 1.1 / 18

time, t = 0.061 s, converting to milliseconds, we have, time, t = 61 ms

6 0

3 years ago

Allen and Jason are chucking a speaker around. On one particular throw, Allen throws the speaker, which is playing a pure tone o

Sholpan [36]

Answer:

Explanation:

We shall apply Doppler's effect of sound .

speaker is the source , Jason is the observer . Source is moving at 10 m /s , observer is moving at 6 m/s .

apparent frequency = $f_o\times\frac{V+v_o}{ V-v_s}$

V is velocity of sound , v₀ is velocity of observer and v_s is velocity of source and f_o is real frequency of source .

Here V = 340 m/s , v₀ is 6 m/s , v_s is 10 m/s . f_o = f

apparent frequency = $f\times \frac{340+6}{340-10}$

= $f\times \frac{346}{330}$

So m = 346 , n = 330 .

8 0

3 years ago