The answer is B. light is reflected off the shirt
Answer:
1.35 g
Explanation:
Data Given:
mass of Potassium Permagnate (KMnO₄) = 3.34 g
Mass of Oxygen: ?
Solution:
First find the percentage composition of Oxygen in Potassium Permagnate (KMnO₄)
So,
Molar Mass of KMnO₄ = 39 + 55 + 4(16)
Molar Mass of KMnO₄ = 158 g/mol
Calculate the mole percent composition of Oxygen in Potassium Permagnate (KMnO₄).
Mass contributed by Oxygen (O) = 4 (16) = 64 g
Since the percentage of compound is 100
So,
Percent of Oxygen (O) = 64 / 158 x 100
Percent of Oxygen (O) = 40.5 %
It means that for ever gram of Potassium Permagnate (KMnO₄) there is 0.405 g of Oxygen (O) is present.
So,
for the 3.34 grams of Potassium Permagnate (KMnO₄) the mass of Oxygen will be
mass of Oxygen (O) = 0.405 x 3.34 g
mass of Oxygen (O) = 1.35 g
Answer:
U could use the formula
Explanation:
To calculate the number of atoms in a sample, divide its weight in grams by the amu atomic mass from the periodic table, then multiply the result by Avogadro's number: 6.02 x 10^23
Answer is <span>
Ni²</span>⁺(aq)
+ 6NH₃(aq)
⇌ [Ni(NH₃)₆]²⁺<span>
</span>
<span>When the concentration of Ni²⁺</span><span>(aq) increases, according to the Le Chatelier’s principle
system tries to become equilibrium by reducing the increased factor. To do
that, the concentration of Ni²⁺</span><span>(aq) should be reduced. Hence, the forward reacted should be
promoted to reduce the Ni²⁺</span><span>(aq) concentration</span>.
The volume% of acetone = Ml of acetone/Ml of solution x100
ml of acetone =200ml
ml of solution = 1.60 x1000=1600ml
volume% of acetone is therefore= 200/1600 x100= 12.5%
