Answer:
Chemical Change
Explanation:
It became white and became solid which makes it a chemical change.
Answer:
Option C is correct.
The minimum amount of material that is needed for a fission reaction to keep going is called the critical mass.
Explanation:
Nuclear fission is the term used to describe the breakdown of the nucleus of a parent isotope into daughter nuclei.
Normally, the initial energy supplied for nuclear fission is the energy to initiate the first breakdown of the first set of radioactive isotopes that breakdown. Once that happens, the energy released from the first breakdown is enough to drive further breakdown of numerous isotopas in a manner that leads to more energy generation.
But, for this to be able to be sustained and not fizzle out, a particular amount of radioactive material to undergo nuclear fission must be present. This particular amount is termed 'critical mass'
Hope this Helps!!!
Answer:
The answer to your question is the letter D. a decomposition reaction
Explanation:
This is a brief description of the main chemical reactions.
a) A synthesis reaction is when two reactants are combined to form only one product.
b) A disynthesis reaction. I have not heard about this chemical reaction, I think it does not exist.
c) A combustion reaction is when an organic molecule reacts with oxygen to form carbon dioxide and water.
d) A decomposition reaction is when one reactant splits to form two or more products.
Answer:
partial pressure of gas D Pd = 15.5 kPa
Explanation:
As per the Dalton's law of partial pressure, in a mixture, pressure exerted by each gas when summed gives the total partial pressure exerted by mixture.
P(Total) = P1+P2+P3.....
Given P(Total) = 35.7 kPa
Partial pressure of gas A Pa = 7.8 kPa
Partial pressure of gas B Pb = 3.7 kPa
Partial pressure of gas C Pc = 8.7 kPa
There, Partial pressure of gas D Pd = P(Total) -(Pa+Pb+Pc)
Pd = 35.7-(7.8+3.7+8.7) = 35.7-20.2 kPa = 15.5 kPa
Therefore, partial pressure of gas D Pd = 15.5 kPa
Answer:
4
Explanation:
Ionization energy can be defined as the energy required for an atom to lose its valence electron to form an ion. Hence, it deals with how easily an atom would lose its electron and form an ion. As the valence electrons are lossless bound to the outermost shell, they can easily be lost without much problem or better still they can be lost easily. Hence, the energy change here is small and thus we can conclude that the ionization energy here is low.
The electron affinity works quite differently from the ionization energy. It deals with the way in which a neutral atom attracts an electron to form an ion. For an electron with loose valence electrons, the sure fact is that it does not really need these electrons. Hence, there is no need for an high electron affinity on its part. Thus, we conclude that the electron affinity is also low
