Answer:
I believe that is space i would check just to make sure tho
A garduated cylander, in order to find the amount of water displaced you see how much the water has risen
The mass of carbon dioxide produced from the complete combustion of 4.80 x10^-3 g of methane is 0.0132 grams
calculation
write the equation for combustion of methane (CH4)
CH4 + 2O2 → CO2 + 2H2O
find the moles of CH4 used = mass/molar mass
molar mass of CH4 = 12 +(1 x4) = 16 g/mol
moles =( 4.80 x10^-3 g) / 16 g/mol = 3 × 10^-4 moles
by use of mole ratio between Ch4 to CO2 which is 1:1 the moles of CO2 is also = 3 x10^-4 moles
mass of CO2 is therefore = moles x molar mass of Co2
The molar mass of Co2 = 12 +(16 ×2) = 44 g/mol
mass is therefore = (3 ×10^-4 moles) ×44 g/mol = 0.0132 grams
2 C4H10 + 13 O2 → 8 CO2 + 10H2O
Given, Heat of formation of C4H10 = = -125.7 kJ/molHeat of formation of water = = -241.82 kJ/molHeat of formation of CO2 = = -393.5 kJ/mol
Thus, enthalpy of combustion = ΔH = ∑Hproducts - ∑Hreactants = 8 + 10 - 2 = (-393.5X8) + (-241.82X10) - (-125.7X2) = -5314.8 kJ/mol
This energy would result in combustion of 2 moles of butane∴ For 1 mole, energy required for combustion of butane = -5314.8/2 = -2657.4 kJ/mol
Answer:
This is the tendency for particles in suspension to settle out of fluid in which they are contained and come to rest against a barrier.
Explanation:
In sedimentation, the particles are in a fluid and under the influence of forces , for example, gravitational forces, they settle and then come to rest when faced with a barrier.
The settling process is the process in which the particles fall out of liquid and sedimentation is the end of the process.