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klasskru [66]
3 years ago
12

What states can electrons exist in?

Chemistry
2 answers:
balandron [24]3 years ago
5 0

Answer:

they can exist in B electron clouds or energy levels

Explanation:

Whitepunk [10]3 years ago
5 0

Answer:

i think that its in phase and out of phase

Explanation:

that's the answer that i used

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Marie Curie named polonium in honor of Poland. 1. True or 2. False
natali 33 [55]
<span>Radium and Polonium were named in honor of Marie Curie.
SO yeh true
Hope this helps!
:)
</span>
7 0
3 years ago
elect all statements that correctly describe the stability of eclipsed and staggered conformers. Multiple select question. Stagg
alisha [4.7K]

Staggered conformers are lower in energy than eclipsed conformers , Option A is the right answer.

<h3>What are Eclipsed and Staggered Confirmation ?</h3>

The arrangement of atoms in molecule such that  the dihedral angle formed is 60 degree is called Staggered Conformation and the arrangement of atoms in which the dihedral angle is 0 degree is called Eclipsed Confirmation

Among the given statements

The statement that best describe the stability of Staggered Conformers and eclipsed conformers is Staggered conformers are lower in energy than eclipsed conformers .

To know more about Eclipsed and Staggered Confirmation

brainly.com/question/27852131

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4 0
2 years ago
bp’s efforts to close the blowout preventer and install a containment dome following an explosion on the deepwater horizon drill
Eduardwww [97]

The British Petroleum (bp's) effort to close the blowout preventer and install a containment dome following an explosion on the deepwater horizon drilling rig is an example of <u>regulatory policy </u>change.

The deepwater horizon drilling rig is a semi-submersible, transportable, floating, flexibly oriented drilling rig that could work in sea depths of up to 10,000 feet which is approximately 3,000 meters.

During the explosion that occurred in April 2010, British Petroleum made several efforts to contain the damages made and to prevent further outbreaks of disasters.

Part of the changes was shifting from a blowout preventer that has a specialized valve to seal, manage, and monitor oil and gas wells in order to prevent blowouts to a containment dome (a crucial component of a system meant to control an oil well's underwater blowout).

Therefore, we can conclude that the British Petroleum (bp's) effort to close the blowout preventer and install a containment dome following an explosion on the deepwater horizon drilling rig is an example of <u>regulatory policy </u>change.

Learn more about deepwater horizon drilling rig here:

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6 0
3 years ago
Identify the polynomial.<br><br> x3- y3 + z<br><br> monomial<br><br> binomial<br><br> trinomial
Firdavs [7]

Answer: Option (c) is the correct answer.

Explanation:

A monomial is defined as an algebraic expression in which there is only one term present.

For example, 3x is a monomial.

A binomial is defined as an expression where there will be two terms present. For example, (x^{2} + y^{2}) is a binomial.

A polynomial is defined as an algebraic expression which contains more than two terms.

For example, x^{3} - y^{3} + z is a polynomial.

Thus, we can conclude that the given expression x^{3} - y^{3} + z is a polynomial.

6 0
3 years ago
1.12g H2 is allowed to react with 9.60 g N2, producing 1.23 g NH3.
andriy [413]

Answer:

A. m_{NH_3}^{theo} =1.50gNH_3

B. Y=82.2\%

Explanation:

Hello!

In this case, since the undergoing chemical reaction between nitrogen and hydrogen is:

N_2+3H_2\rightarrow 2NH_3

Thus we proceed as follows:

A. Here, we first need to compute the moles of ammonia yielded by each reactant, in order to identify the limiting one:

n_{NH_3}^{by \ H_2}=1.12gH_2*\frac{1molH_2}{2.02gH_2}*\frac{2molNH_3}{3molH_2}=0.370molNH_3\\\\  n_{NH_3}^{by \ N_2}=1.23gN_2*\frac{1molN_2}{28.02gN_2}*\frac{2molNH_3}{1molN_2}=0.0878molNH_3

Thus, since nitrogen yields the fewest moles of ammonia, we realize it is the limiting reactant, so the theoretical yield, in grams, of ammonia is:

m_{NH_3}^{theo}=0.0878mol*\frac{17.04gNH_3}{1molNH_3} =1.50gNH_3

B. Finally, since the actual yield of ammonia is 1.23, the percent yield turns out:

Y=\frac{1.23gNH_3}{1.50gNH_3} *100\%\\\\Y=82.2\%

Best regards!

5 0
3 years ago
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