Answer:
Step-by-step explanation:
we know that
The area of a regular hexagon is the same that the area of 6 equilateral triangles
The area of 6 equilateral triangles applying the law of sines is equal to
![A=6[\frac{1}{2}b^2sin(60^o)]](https://tex.z-dn.net/?f=A%3D6%5B%5Cfrac%7B1%7D%7B2%7Db%5E2sin%2860%5Eo%29%5D)
where
b is the length side of the regular hexagon
we have
substitute
![A=6[\frac{1}{2}(10)^2sin(60^o)]](https://tex.z-dn.net/?f=A%3D6%5B%5Cfrac%7B1%7D%7B2%7D%2810%29%5E2sin%2860%5Eo%29%5D)
Answer:
Step-by-step explanation:
x+5=0
x=-5
-5) 16 80 1 5
| -80 0 -5
____________
| 16 0 1 | 0
quotient=16x²+1
Remainder=0
<h2>Sorry, But I don't know!!</h2>
Answer:
The answer is option D.
Step-by-step explanation:
(4a - b)(2a - 3b)
Expand the terms
We have
8a² - 12ab - 2ab + 3b²
Which is
8a² - 14ab + 3b²
That's option D.
Hope this helps you
Simplify both sides of the equation
-25(x-4)=-55(x-10)
(-25)(x) + (-25)(-4)=(-55)(x) + (-55) (-10)
Distribute
-25x+100=-55x+550
Add 55x to both sides
-25x+100+55x=-55x+550+55x
30x+100-100=550-100
subtract 100 from both sides
30x+100-100=550-100
30x=450
divide both sides by 30
30x/30=450/30
x= 15
The value of x is 15
I hope that's help you my friend !
