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mars1129 [50]
3 years ago
12

The product of two integers is 16 find the numbers if their sum is a minimum

Mathematics
1 answer:
Masteriza [31]3 years ago
3 0
<span>Let n, n+2, and n+4 represent the three consecutive even integers. Or 2 in your case</span>
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Find the solutions to the equation below.
Volgvan

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Move all terms to the left side and set equal to zero. Then set each factor equal to zero

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Can you help me please? explain why its a yes or no.​
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Step-by-step explanation: it’s a no because. 19 - 15 does not equal out to 7 19 - 15 is 4 and that’s the wrong answer for 19 -15


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6 0
3 years ago
25 POINTS AND BRAINLIEST PLEASE HELP ASAP
dexar [7]
M is a midpoint of BC so:

M=\left(\dfrac{\boxed{2}\boxed{a}+a}{\boxed{2}},\dfrac{\boxed{0}+b}{2}\right)=\left(\dfrac{\boxed{3}\boxed{a}}{\boxed{2}},\dfrac{\boxed{b}}{\boxed{2}}\right)

Length of MA:

MA=\sqrt{\left(\dfrac{\boxed{3}a}{2}\boxed{-}\boxed{0}\right)^2+\left(\dfrac{\boxed{b}}{2}\boxed{-}\boxed{0}\right)^2}=\\\\\\=&#10;\sqrt{\left(\dfrac{\boxed{3}a}{\boxed{2}}\right)^2+\left(\dfrac{b}{2}\right)^2}=\sqrt{\dfrac{\boxed{9}a^2}{\boxed{4}}+\dfrac{\boxed{b}^2}{\boxed{4}}}

Length of NB:

NB=\sqrt{\left(\dfrac{a}{2}\boxed{-}\boxed{2}a\right)^2+\left(\dfrac{b}{2}\boxed{-}\boxed{0}\right)^2}=\\\\\\=\sqrt{\left(\dfrac{a}{2}\boxed{-}\dfrac{\boxed{4}\boxed{a}}{2}\right)^2+\left(\dfrac{b}{2}-\boxed{0}\right)^2}=\\\\\\&#10;\sqrt{\left(\dfrac{-3a}{2}\right)^2+\left(\dfrac{b}{\boxed{2}}\right)^2}=\sqrt{\dfrac{\boxed{9}a^2}{\boxed{4}}+\dfrac{\boxed{b}^2}{\boxed{4}}}
5 0
3 years ago
Read 2 more answers
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