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siniylev [52]
3 years ago
11

2(x-3) = (x-1) + 7 Please show your steps!!

Mathematics
2 answers:
melamori03 [73]3 years ago
7 0
2(x-3)=(x-1)+7
2x-6=x+6
x=12. Hope it help!
andre [41]3 years ago
6 0
Simplify the equation.

First, distribute the 2 in the left side of the equation.
Resulting in: 2x-6 = (x-1) + 7

Second, remove the parentheses form the right side of the equation (there is nothing to distribute there).
Resulting in: x - 1 + 7

Now simplify the right side of the equation by subtracting the 1 from the 7.
Resulting in: x + 6

Our goal is to isolate the x to the left side, and the numerals to the right side.
With that in mind, add the 6 (from the right side) to both sides. This cancels out the 6 on the right side.
Resulting in: 2x = 12

Lastly, in order to fully isolate the variable (x), we divide both sides by 2.
Resulting in: x = 6

Hope this helps.
You might be interested in
A right angled triangle has sides of length 9cm, 12cm and 15cm. Calculate its area in square centimetres.
Dmitriy789 [7]

The area of a right angled triangle with sides of length 9cm, 12cm and 15cm in square centimeters is 54 sq cm.

The formula to calculate the area of a right triangle is given by:

Area of Right Triangle, A = (½) × b × h square units

Where, “b” is the base (adjacent side) and “h” is the height (perpendicular side). Hence, the area of the right triangle is the product of base and height and then divide the product by 2.

We know that the hypotenuse is the longest side. So, the area of a right angled triangle will be half of the product of the remaining two sides.

Given sides of the triangle:

a=9cm

b=12cm

c=15cm

From this we know that the hypotenuse is c. Are of the triangle will be obtained by the other two sides.

∴Area = \frac{1}{2} x 9 x 12

= 54cm^{2}

5 0
1 year ago
Im confused and i need help please help
denis23 [38]

Answer:

C

Step-by-step explanation:

8 0
3 years ago
How many different triangles can you make with 14cm, 10cm and 50cm sides?
vovangra [49]

Answer:

You can make NO triangles.

When given 3 sides of a triangle, The longest side must be LESS than the sum of the other 2 sides.

Longest Side = 50 cm

50 is NOT less than 14 + 10, therefore, we have no triangle.


Step-by-step explanation:


8 0
3 years ago
Rina draws a plan of her school on a coordinate grid. She plots the school gate at point p(-8,-1) and the library at point Q(2,5
natka813 [3]

Answer:

The coordinates of the science lab is:

x = -14/3  ,  y = 1

Step-by-step explanation:

∵ P is (-8 , -1) and Q is (2 , 5)

∵ The point of the science lab is (x , y)

∵ The science lab point divided PQ at ratio 2 : 1 from Q (two thirds PQ)

∴ x=\frac{m_{1}x_{p}+m_{2}x_{q}}{m_{1}+m_{2}}

∴ y=\frac{m_{1}y_{p}+m_{2}y_{q}}{m_{1}+m_{2}}

∴ x=\frac{2(-8)+1(2)}{1+2}=\frac{-14}{3}

∴ y=\frac{2(-1)+1(5)}{2+1}=\frac{3}{3}=1

∴ The point of science lab = (-14/3 , 1)

5 0
3 years ago
By [n][n] we denote the set {1,…,n}. A function f:[m]→[n] is called monotone if f(i) \leq f(j)f(i)≤f(j)whenever i < ji
Dafna11 [192]

Answer:

There are a total of  { 6 \choose 3} = 20 functions.

Step-by-step explanation:

In order to define an injective monotone function from [3] to [6] we need to select 3 different values fromm {1,2,3,4,5,6} and assign the smallest one of them to 1, asign the intermediate value to 2 and the largest value to 3. That way the function is monotone and it satisfies what the problem asks.

The total way of selecting injective monotone functions is, therefore, the total amount of ways to pick 3 elements from a set of 6. That number is the combinatorial number of 6 with 3, in other words

{6 \choose 3} = \frac{6!}{3!(6-3)!} = \frac{720}{6*6} = \frac{720}{36} = 20  

3 0
3 years ago
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