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3 years ago

Simplify the following:

Mathematics

1 answer:

DIA [1.3K]3 years ago

3 0

Answer:

5x+23

Step-by-step explanation:

3(x+1) - 4(2x-5) + 10x

3x+3 - 8x+20 + 10x

(3x-8x+10x = 5x)

(3+20 = 23)

Therefore, answer is 5x-23. :)

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Growth Models 19515. In 1968, the U.S. minimum wage was $1.60 per hour. In 1976, the minimum wagewas $2.30 per hour. Assume the

VikaD [51]

In general, the exponential growth function is given by the formula below

$f(x)=a(1+r)^x$

Where a and r are constants, and x is the number of time intervals.

In our case, n=0 for 1960; therefore, 1968 is n=8,

$\begin{gathered} f(8)=a(1+r)^8 \\ \text{and} \\ f(8)=1.6 \\ \Rightarrow1.6=a(1+r)^8 \end{gathered}$

And 1976 is n=16

$\begin{gathered} f(16)=a(1+r)^{16} \\ \text{and} \\ f(16)=2.3 \\ \Rightarrow2.3=a(1+r)^{16} \end{gathered}$

Solve the two equations simultaneously, as shown below

$\begin{gathered} \frac{1.6}{(1+r)^8}=a \\ \Rightarrow2.3=\frac{1.6}{(1+r)^8}(1+r)^{16} \\ \Rightarrow2.3=1.6(1+r)^8 \\ \Rightarrow\frac{2.3}{1.6}=(1+r)^8 \\ \Rightarrow(\frac{2.3}{1.6})^{\frac{1}{8}}=(1+r)^{}^{} \\ \Rightarrow r=(\frac{2.3}{1.6})^{\frac{1}{8}}-1 \\ \Rightarrow r=0.0464078 \end{gathered}$

Solving for a,

$\begin{gathered} r=0.0464078 \\ \Rightarrow a=\frac{1.6}{(1+0.0464078)^8}=1.113043\ldots \end{gathered}$

a) Thus, the equation is

$\Rightarrow f(n)=1.113043\ldots(1+0.0464078\ldots)^n$

b) 1960 is n=0; thus,

$f(0)=1.113043\ldots(1+0.0464078\ldots)^0=1.113043\ldots$

The answer to part b) is $1.113043... per hour

c)1996 is n=36

$\begin{gathered} f(36)=1.113043\ldots(1+0.0464078\ldots)^{36} \\ \Rightarrow f(36)=5.6983\ldots \end{gathered}$

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