1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
RUDIKE [14]
3 years ago
12

I

Mathematics
1 answer:
Alinara [238K]3 years ago
3 0

Answer: C

Step-by-step explanation:

You might be interested in
Tamara bought a $22 mailbox using a 10% off coupon David bought an identical mailbox for $19.95 at a different store
MAVERICK [17]

Answer:David bought an identical mailbox for $ 19.95 at a different store.

Step-by-step explanation:

David bought an identical mailbox for $ 19.95 at a different store. you can buy a same mailbox but for different prices you have 22 dollars you have a 110 percent off you dont have enough

4 0
2 years ago
The Los Angeles Times regularly reports the air quality index for various areas of Southern California. A sample of air quality
egoroff_w [7]

Answer:

1. (a) 32     (b) 8

2. (a) 48.33    (b) 92.75    (c) 9.63

3.  We observe that sample mean of air quality index in Pomona is higher that that of Anaheim which indicates that the level of air pollution is higher in Pomona and there is more health concern here.

On the other hand, the variation in air quality index is higher in Anaheim than in Pomona as Anaheim has higher variance and standard deviation for air quality index which means that there are not much fluctuations in air quality index in Pomona.  

Step-by-step explanation:

First arranging our data of air quality index values for Pomona in ascending order, we get : 28, 42, 45, 48, 49, 50, 55, 58, 60.

  1. (a) Range is given by the formula :

                      Highest value in data - Lowest value in data = 60 - 28 = 32

        (b) Interquartile rage = Third quartile - First quartile

                                           = Q_3 - Q_1

             Q_1 =  (\frac{n-1}{4} )^{th} observation in the data = 2^{nd} obs. { Because n = 9}

                 Therefore, Q_1 = 42.

             Q_3 = (3Q_1)^{th} obs. = (3 x 2 ) = 6^{th} obs = 50

             So, Interquartile rage = 50 - 42 = 8.

     2. (a) Sample mean formula =  \frac{\sum X_i}{n} = \frac{28+ 42+ 45+ 48+ 49+ 50+ 55+ 58+ 60}{9} = 48.33

         (b) Sample variance formula = \frac{\sum (X_i - Xbar)^{2}}{n-1} where Xbar = Sample mean

                                                         = 92.75

          (c) Sample standard deviation  formula = \sqrt{variance} = \sqrt{92.75} = 9.63.

     3. Given that a sample of air quality index readings for Anaheim has   sample mean of 48.3, a sample variance of 136, and a sample standard deviation of 11.66.

We observe that sample mean of air quality index in Pomona is higher that that of Anaheim which indicates that the level of air pollution is higher in Pomona and there is more health concern here.

On the other hand, the variation in air quality index is higher in Anaheim than in Pomona as Anaheim has higher variance and standard deviation for air quality index which means that there are not much fluctuations in air quality index in Pomona.  

                                       

7 0
3 years ago
A rectangle is inside a circle with a 5 cm radius.
MrRa [10]

Answer:  30.5 cm²

To get the the area of the rectangle all we have to do is:

Rectangle Area = 6 × 8 = 48 cm²

Same thing to the circle, multiply the radius and pi:

Circle Area = 3.14 x 5² = 78.5 cm²

We have to subtract the two areas to find the shaded area.

78.5 - 48 = 30.5 cm²

I hope this helps!

3 0
3 years ago
In June 2005, a CBS News/NY Times poll asked a random sample of 1,111 U.S. adults the following question: "What do you think is
Shtirlitz [24]

Answer:

The appropriate null hypothesis is H_0: p = 0.25

The appropriate alternative hypothesis is H_1: p < 0.25

Step-by-step explanation:

Exactly a year prior to this poll, in June of 2004, it was estimated that roughly 1 out of every 4 U.S. adults believed (at that time) that the war in Iraq was the most important problem facing the country.

At the null hypothesis, we test if the proportion is still the same, that is, of \frac{1}{4} = 0.25. So

H_0: p = 0.25

We would like to test whether the 2005 poll provides significant evidence that the proportion of U.S. adults who believe that the war in Iraq is the most important problem facing the U.S. has decreased since the prior poll.

Decreased, so at the alternative hypothesis, it is tested if the proportion is less than 0.25, that is:

H_1: p < 0.25

3 0
3 years ago
Help please i will give brainliest
tangare [24]

Answer:

7\geqr

Step-by-step explanation:

-1.3\geq2.9-0.6r

-2.9   -2.9

-4.2 ≥ -0.6r

/-0.6    /-0.6

7   ≥   r

8 0
3 years ago
Other questions:
  • 1. If 8 is 40% of a value, what is the value?
    7·2 answers
  • [HELP ASAP] Triangle angles:
    14·1 answer
  • What is the least perimeter of are tangle with an ware of 32 square feet
    15·2 answers
  • Please tell me the what to do with this problem
    6·2 answers
  • Micky spent 3 1/4 hours practicing his trumpet. He needs to spend 5 1/2 hours receive an A in band. How many hours does Mickey n
    6·1 answer
  • Gabriel has dinner at a cafe and the cost of her meal is $45.00 because of the service she wants to leave a 15% tip
    15·1 answer
  • What are the solutions for f(x)=3x2-x+3?
    8·1 answer
  • For the experiment of drawing a single card
    15·2 answers
  • Bob is filling his 7000-gallon swimming
    6·1 answer
  • Which number is in the solution set of the inequality -5x - 7 &gt; 28?
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!