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trapecia [35]
2 years ago
6

The product of two consecutive positive integers is 812. What is the value of the lesser integer?

Mathematics
1 answer:
leonid [27]2 years ago
5 0
The value of the lesser integer is 28
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en una casa construida con madera el tejado se sostiene con una estructura triangular en el que se utilizan ángulos complementar
professor190 [17]

Answer:

Si me dieras una imagen con esto, podría responderla fácilmente, pero no hay una imagen o modelo para ayudar a disculparme.

Step-by-step explanation:

lo siento, tal vez vuelva a publicarlo con un modelo o una imagen para que pueda ayudar

6 0
2 years ago
HURYY PLEASE EXPLAIN ASAP!!!
Wittaler [7]

Answer:

The answer is 527.5km^3 .

Step-by-step explanation:

The formula for cylinders is πr2h. (pie times twice the height)

3.14(12)(2)(7) = 527.52

5 0
3 years ago
Read 2 more answers
Find the angle between u =the square root of 5i-8j and v =the square root of 5i+j.
fenix001 [56]

Answer:

The angle between vector \vec{u} = 5\, \vec{i} - 8\, \vec{j} and \vec{v} = 5\, \vec{i} + \, \vec{j} is approximately 1.21 radians, which is equivalent to approximately 69.3^\circ.

Step-by-step explanation:

The angle between two vectors can be found from the ratio between:

  • their dot products, and
  • the product of their lengths.

To be precise, if \theta denotes the angle between \vec{u} and \vec{v} (assume that 0^\circ \le \theta < 180^\circ or equivalently 0 \le \theta < \pi,) then:

\displaystyle \cos(\theta) = \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|}.

<h3>Dot product of the two vectors</h3>

The first component of \vec{u} is 5 and the first component of \vec{v} is also

The second component of \vec{u} is (-8) while the second component of \vec{v} is 1. The product of these two second components is (-8) \times 1= (-8).

The dot product of \vec{u} and \vec{v} will thus be:

\begin{aligned} \vec{u} \cdot \vec{v} = 5 \times 5 + (-8) \times1 = 17 \end{aligned}.

<h3>Lengths of the two vectors</h3>

Apply the Pythagorean Theorem to both \vec{u} and \vec{v}:

  • \| u \| = \sqrt{5^2 + (-8)^2} = \sqrt{89}.
  • \| v \| = \sqrt{5^2 + 1^2} = \sqrt{26}.

<h3>Angle between the two vectors</h3>

Let \theta represent the angle between \vec{u} and \vec{v}. Apply the formula\displaystyle \cos(\theta) = \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|} to find the cosine of this angle:

\begin{aligned} \cos(\theta)&= \frac{\vec{u} \cdot \vec{v}}{\| u \| \cdot \| v \|} = \frac{17}{\sqrt{89}\cdot \sqrt{26}}\end{aligned}.

Since \theta is the angle between two vectors, its value should be between 0\; \rm radians and \pi \; \rm radians (0^\circ and 180^\circ.) That is: 0 \le \theta < \pi and 0^\circ \le \theta < 180^\circ. Apply the arccosine function (the inverse of the cosine function) to find the value of \theta:

\displaystyle \cos^{-1}\left(\frac{17}{\sqrt{89}\cdot \sqrt{26}}\right) \approx 1.21 \;\rm radians \approx 69.3^\circ .

3 0
3 years ago
I need help..... I don't understand at all
cluponka [151]
I think you have to estimate to a whole so 2 1/2 would be 3
8 0
3 years ago
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PLEASE HELP!! good luck will be brought back to you ❤️Which statement about the triangles is true?
vekshin1
I think it is the first one
3 0
3 years ago
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