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3 years ago

I need the answer to b and c. Pls Help!

Mathematics

1 answer:

mina [271]3 years ago

6 0

Answer:

b) ? = 0

c) ? = 10

Step-by-step explanation:

By observing the equations, we notice a pattern. The resulting number is always equal to one number doubled added to the other number. Therefore, set up two equations as follows:

2(7)+y=14

2x+3=23

Assume that the provided number is the doubled number if it is a perfect factor, with 2, and assume the provided number is not the provided number if the difference between the answer and it is an even number.

Solve:

14+y=14

y=0

2x+3=23

2x=20

x=10

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andreyandreev [35.5K]

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3 years ago

Simplify the following expression.

HACTEHA [7]

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3 years ago

Please help-many points

kenny6666 [7]

Relatively prime means there are no number greater than 1 that divides them both.

Find the GCF for each set:

A. 68 and 119

68: 1 , 2, 4, 17, 34,68

119: 1, 7, 17

Both numbers can be divided by 1 or 17 so are not relative.

40 and 395

are both divisible by 1 and 5 so are not relative.

C. 119 and 715

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D. 63 and 56

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7 0

3 years ago

Which expression is equivalent to *picture attached*

DiKsa [7]

Answer:

The correct option is;

$4 \left (\dfrac{50 (50+1) (2\times 50+1)}{6} \right ) +3 \left (\dfrac{50(51) }{2} \right )$

Step-by-step explanation:

The given expression is presented as follows;

$\sum\limits _{n = 1}^{50}n\times \left (4\cdot n + 3 \right )$

Which can be expanded into the following form;

$\sum\limits _{n = 1}^{50} \left (4\cdot n^2 + 3 \cdot n\right ) = 4 \times \sum\limits _{n = 1}^{50} \left n^2 + 3 \times\sum\limits _{n = 1}^{50} n$

From which we have;

$\sum\limits _{k = 1}^{n} \left k^2 = \dfrac{n \times (n+1) \times(2n+1)}{6}$

$\sum\limits _{k = 1}^{n} \left k = \dfrac{n \times (n+1) }{2}$

Therefore, substituting the value of n = 50 we have;

$\sum\limits _{n = 1}^{50} \left k^2 = \dfrac{50 \times (50+1) \times(2\cdot 50+1)}{6}$

$\sum\limits _{k = 1}^{50} \left k = \dfrac{50 \times (50+1) }{2}$

Which gives;

$4 \times \sum\limits _{n = 1}^{50} \left n^2 = 4 \times \dfrac{n \times (n+1) \times(2n+1)}{6} = 4 \times \dfrac{50 \times (50+1) \times(2 \times 50+1)}{6}$

$3 \times\sum\limits _{n = 1}^{50} n = 3 \times \dfrac{n \times (n+1) }{2} = 3 \times \dfrac{50 \times (51) }{2}$

$\sum\limits _{n = 1}^{50}n\times \left (4\cdot n + 3 \right ) = 4 \times \dfrac{50 \times (50+1) \times(2\times 50+1)}{6} +3 \times \dfrac{50 \times (51) }{2}$

Therefore, we have;

$4 \left (\dfrac{50 (50+1) (2\times 50+1)}{6} \right ) +3 \left (\dfrac{50(51) }{2} \right )$ .

4 0

3 years ago

Amanda bought a 6 cup bag of shredded cheese for $6.89. She used 2.25 cups to make lasagna and 1.25 cups to make pizza. How much

Anna11 [10]

Answer:

3.50 cups

Step-by-step explanation:

6-2.25=4.75

4.75-1.25=3.50

5 0

3 years ago