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Stells [14]
3 years ago
15

I need the answer to b and c. Pls Help!

Mathematics
1 answer:
mina [271]3 years ago
6 0

Answer:

b) ? = 0

c) ? = 10

Step-by-step explanation:

By observing the equations, we notice a pattern. The resulting number is always equal to one number doubled added to the other number. Therefore, set up two equations as follows:

2(7)+y=14

2x+3=23

Assume that the provided number is the doubled number if it is a perfect factor, with 2, and assume the provided number is not the provided number if the difference between the answer and it is an even number.

Solve:

14+y=14

y=0

2x+3=23

2x=20

x=10

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andreyandreev [35.5K]
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Simplify the following expression.
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3 years ago
Please help-many points
kenny6666 [7]

Relatively prime means there are no number greater than 1 that divides them both.

Find the GCF for each set:

A. 68 and 119

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119: 1, 7, 17

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B.

40 and 395

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C. 119 and 715

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3 years ago
Which expression is equivalent to *picture attached*
DiKsa [7]

Answer:

The correct option is;

4 \left (\dfrac{50 (50+1) (2\times 50+1)}{6} \right ) +3  \left (\dfrac{50(51) }{2} \right )

Step-by-step explanation:

The given expression is presented as follows;

\sum\limits _{n = 1}^{50}n\times \left (4\cdot n + 3  \right )

Which can be expanded into the following form;

\sum\limits _{n = 1}^{50} \left (4\cdot n^2 + 3  \cdot n\right ) = 4 \times \sum\limits _{n = 1}^{50} \left  n^2 + 3  \times\sum\limits _{n = 1}^{50}  n

From which we have;

\sum\limits _{k = 1}^{n} \left  k^2 = \dfrac{n \times (n+1) \times(2n+1)}{6}

\sum\limits _{k = 1}^{n} \left  k = \dfrac{n \times (n+1) }{2}

Therefore, substituting the value of n = 50 we have;

\sum\limits _{n = 1}^{50} \left  k^2 = \dfrac{50 \times (50+1) \times(2\cdot 50+1)}{6}

\sum\limits _{k = 1}^{50} \left  k = \dfrac{50 \times (50+1) }{2}

Which gives;

4 \times \sum\limits _{n = 1}^{50} \left  n^2 =  4 \times \dfrac{n \times (n+1) \times(2n+1)}{6} = 4 \times \dfrac{50 \times (50+1) \times(2 \times 50+1)}{6}

3  \times\sum\limits _{n = 1}^{50}  n = 3  \times \dfrac{n \times (n+1) }{2} = 3  \times \dfrac{50 \times (51) }{2}

\sum\limits _{n = 1}^{50}n\times \left (4\cdot n + 3  \right ) = 4 \times \dfrac{50 \times (50+1) \times(2\times 50+1)}{6} +3  \times \dfrac{50 \times (51) }{2}

Therefore, we have;

4 \left (\dfrac{50 (50+1) (2\times 50+1)}{6} \right ) +3  \left (\dfrac{50(51) }{2} \right ).

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Answer:

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Step-by-step explanation:

6-2.25=4.75

4.75-1.25=3.50

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