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3 years ago

Corinne is paid weekly $356.78. What is her yearly salary?

Mathematics

2 answers:

Andru [333]3 years ago

8 0

Answer:

The yearly salary of Corinne is $ 18552.56

Step-by-step explanation:

Given : Corinne is paid weekly $356.78

We have to find the yearly salary of Corinne.

We know one year has 52 weeks,

Since, Corinne is paid weekly $356.78

To find yearly salary simply multiply weekly pay by 52

So , her yearly paid will be $356.78 × 52 = $ 18552.56

Thus, the yearly salary of Corinne is $ 18552.56

sveticcg [70]3 years ago

6 0

There are 52 weeks in a year so multiply 356.78 by 52 and you get a yearly salary of 18,552.56 (she probably didnt went to college)

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4x+10-4(-4x+5) some one help I’m a freshmen

Umnica [9.8K]

Answer:

-12x - 10 or -2(6x +5)

Step-by-step explanation:

4x + 10 - 4(-4x + 5)

first, distribute the -4 among the parentheses

4x + 10 - 16x - 20

combine like terms

-12x - 10

if they want you to take it further, take out a -2

-2(6x + 5)

4 0

3 years ago

Suppose that a box contains 8 cameras and that 4 of them are defective. A sample of 2 cameras is selected at random with replace

Dafna1 [17]

The Expected value of XX is 1.00.

Given that a box contains 8 cameras and that 4 of them are defective and 2 cameras is selected at random with replacement.

The probability distribution of the hypergeometric is as follows:

$P(x,N,n,M)=\frac{\left(\begin{array}{l}M\\ x\end{array}\right)\left(\begin{array}{l}N-M\\ n-x\end{array}\right)}{\left(\begin{array}{l} N\\ n\end{array}\right)}$

Where x is the success in the sample of n trails, N represents the total population, n represents the random sample from the total population and M represents the success in the population.

The probability distribution for X is obtained as below:

From the given information, let X be a random variable, that denotes the number of defective cameras following hypergeometric distribution.

Here, M = 4, n=2 and N=8

The probability distribution of X is obtained below:

The probability distribution of X is,

$P(X=x)=\frac{\left(\begin{array}{l}5\\ x\end{array}\right)\left(\begin{array}{l}8-5\\ 2-x\end{array}\right)}{\left(\begin{array}{l} 8\\ 2\end{array}\right)}$

The probability distribution of X when X=0 is

$\begin{aligned}P(X=0)&=\frac{\left(\begin{array}{l}4\\ 0\end{array}\right)\left(\begin{array}{l}8-4\\ 2-0\end{array}\right)}{\left(\begin{array}{l} 8\\ 2\end{array}\right)}\\ &=\frac{\left(\begin{array}{l}4\\ 0\end{array}\right)\left(\begin{array}{l}4\\ 2\end{array}\right)}{\left(\begin{array}{l} 8\\ 2\end{array}\right)}\\ &=\frac{\left[\left(\frac{4!}{(4-0)!0!}\right)\times \left(\frac{4!}{(4-2)!2!}\right)\right]}{\left(\frac{8!}{(8-2)!2!}\right)}\\ &=0.21\end$

The probability distribution of X when X=1 is

$\begin{aligned}P(X=1)&=\frac{\left(\begin{array}{l}4\\ 1\end{array}\right)\left(\begin{array}{l}8-4\\ 2-1\end{array}\right)}{\left(\begin{array}{l} 8\\ 2\end{array}\right)}\\ &=\frac{\left(\begin{array}{l}4\\ 1\end{array}\right)\left(\begin{array}{l}4\\ 1\end{array}\right)}{\left(\begin{array}{l} 8\\ 2\end{array}\right)}\\ &=\frac{\left[\left(\frac{4!}{(4-1)!1!}\right)\times \left(\frac{4!}{(4-1)!1!}\right)\right]}{\left(\frac{8!}{(8-2)!2!}\right)}\\ &=0.57\end$

The probability distribution of X when X=2 is

$\begin{aligned}P(X=2)&=\frac{\left(\begin{array}{l}4\\ 2\end{array}\right)\left(\begin{array}{l}8-4\\ 2-2\end{array}\right)}{\left(\begin{array}{l} 8\\ 2\end{array}\right)}\\ &=\frac{\left(\begin{array}{l}4\\ 2\end{array}\right)\left(\begin{array}{l}4\\ 0\end{array}\right)}{\left(\begin{array}{l} 8\\ 2\end{array}\right)}\\ &=\frac{\left[\left(\frac{4!}{(4-2)!2!}\right)\times \left(\frac{4!}{(4-0)!0!}\right)\right]}{\left(\frac{8!}{(8-2)!2!}\right)}\\ &=0.21\end$

Use E(X)=∑xP(x) to find the expected values of a random variable X.

The expected values of a random variable X is obtained as shown below:

The expected value of X is,

E(X)=∑xP(x-X)

E(X)=[(0×0.21)+(1×0.57)+(2×0.21)]

E(X)=[0+0.57+0.42]

E(X)=0.99≈1

Hence, the binomial probability distribution of XX when X=0 is 0.21, when X=1 is 0.57 and when X=2 is 0.21 and the expected value of XX is 1.00.

Learn about Binomial probability distribution from here brainly.com/question/10559687

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1 year ago

the average person loses about 8×10 strands of hair how many strands of hair does the average person lose in 9 days

Masteriza [31]

It depends you mean per day or if so..... it is 720

3 0

3 years ago

Read 2 more answers

Only need help on number 8. Thanks in advance. Must show work. If you do I will give you brainliest. :)

marishachu [46]

Answer:

Necklace cost $144 and bracelet cost $48

Step-by-step explanation:

call x is the price of necklace, y is the price of bracelet

because necklace cost 3 time as much as the bracelet

=> 3x = y

A necklace and a bracelet cost $192

=> x + y = 192

=>set of equations

3x = y and x+y = 192

x= 3y and 3y + y = 192

=> y = 48 and x = 3 . 48 = 144

6 0

3 years ago

Is the solution to the inequality?<br><br> 1/4+x < 5/6

klemol [59]

Solving the inequality: $\frac{1}{4}+x$ we get $x$

Step-by-step explanation:

We need to solve the inequality: $\frac{1}{4}+x$

Solving:

$\frac{1}{4}+x$

Adding -1/4 on both sides:

$\frac{1}{4}+x-\frac{1}{4}$

So, solving the inequality: $\frac{1}{4}+x$ we get $x$

Keywords: Solving the inequality

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3 years ago