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3 years ago

8 9/10-1 1/5 please answer soon

Mathematics

2 answers:

vazorg [7]3 years ago

5 0

Answer: 7 7/10

Step-by-step explanation:Find LCM Which means LEast common multiple so make 1 1/5 to 1 2/10 .now you can subtract 8 9/10 from 1 2/10 which gives you 7 7/10.

Hope it helps and look at pic below . :)

Paul [167]3 years ago

3 0

Answer: 7 7/10

Step-by-step explanation:

First you have to multiply 1 1/5 by two so that you could subtract it from 8 9/10. Once you do that that’s when you get 7 7/10.

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What are the ordered pairs of the solutions for this system of equations

AleksAgata [21]

Answer:

(3, 6); (-3, 18)

Step-by-step explanation:

We equate the 2 expressions in x :-

x^2 - 2x + 3 = -2x + 12

x^2 - 2x + 2x + 3 - 12 = 0

x^2 - 9 = 0

(x - 3)(x + 3) = 0

So x = 3 or -3.

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When x = -3, f(x) = -2(-3) + 12 = 18.

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3 years ago

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This boils down to simple algebraic manipulation.

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3 years ago

If the circulation for newspaper 1 is 382 thousand more than the circulation for newspaper 2 and their combined is 2502 thousand

goldenfox [79]

If the circulation for newspaper 1 is 382 thousand more than the circulation for newspaper 2 and their combined is 2502 thousand find the circulation for each paper

Answer: Let x be the circulation for newspaper 2.

Then the circulation for newspaper 1 is $x +382$ thousand

We are given the combined circulation of newspaper 1 and newspaper 2 is 2502 thousand

$\therefore x+(x+382)=2502$

$2x+382=2502$

$2x=2502-382$

$2x=2120$

$x=\frac{2120}{2} =1060$

Therefore, the circulation of newspaper 2 is 1060 thousand and circulation of newspaper 1 is 1060 + 382 = 1442 thousand

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3 years ago

Read 2 more answers

What is the correct order of operations for simplifying the expression (x+3)^2-(x^2+9)/2x^2?

kramer

Answer:

The given expression is simplified as $\frac{(x+3)^2-(x^2 +9)} {2x^2} = \frac{3}{x}$

Step-by-step explanation:

Here, the given expression is:

$\frac{(x+3)^2-(x^2 +9)} {2x^2}$

Now, with ALGEBRAIC IDENTITIES:

$(a+b)^2 = a^2 + b^2 + 2ab$

Now, similarly: $(x+3)^2 = x^2 + (3)^2 + 2x(3) = (x^2 + 9 + 6x)$

Now, substituting the values in the given expression, we get:

$\frac{(x+3)^2-(x^2 +9)} {2x^2} \implies \frac{(x^2 + 9 + 6x)-(x^2 +9)} {2x^2}\\= \frac{(x^2 + 9 + 6x-x^2 -9)} {2x^2} \\= \frac{ 6x} {2x^2} = \frac{3}{x}$

Hence, the given expression $\frac{(x+3)^2-(x^2 +9)} {2x^2} = \frac{3}{x}$

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3 years ago