Answer:
Step-by-step explanation:
Given the integrand , before evaluating the integral function, we will need to simplify the function first by applying long division as shown in the attachment.
Hence the partial form of the function
Integrating its partial sum
<em>NB: Find the partial sum calculation also in the attachment. </em>
Answer:
The solved problem is in the photo. Hope it helps.
Answer:
The equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 is
Step-by-step explanation:
Given:
Let,
point A( x₁ , y₁) ≡ ( -2 , 7)
To Find:
Equation of Line that passes through the point (-2,7) and is perpendicular to the line x-6y=42=?
Solution:
..................Given
which can be written as
Where m is the slope of the line
∴
On Comparing we get
The Required line is Perpendicular to the above line.
So,
Product of slopes = - 1
Slope of the required line is -6
Equation of a line passing through a points A( x₁ , y₁) and having slope m is given by the formula,
i.e equation in point - slope form
Now on substituting the slope and point A( x₁ , y₁) ≡ ( -2, 7) and slope = -6 we get
The equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 is