Solve for u:6u+24-8u=-18
1 answer:
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For this case, since the variation is direct then we have a relation of the form:
Where,
k: proportionality constant
To find k we substitute the following data:
y = 16 when x = 8
We have then:
Clearing the value of k we have:
Then, the equation is:
Substituting the value of x = 16 we have:
Answer:
The value of y for x = 16 is:
Let, initial side is a.
When side is n times long, new side na.
Initial volume,
Final volume,
Change in volume,
For, n = 2 :
n = 3 :
n = 10 :
Hence, this is the required solution.
Step-by-step explanation:
To find an unknown side of a right angled triangle we use a theorum called pythagorus theorum..
<h3>Formula :</h3>(Hypotenuse)^2 = (Perpendicular)^2 + (Base)^2
(h)^2 = (p)^2 + (b)^2
<h3>therefore, </h3>(a) hypotenuse = x cm, base = √30 cm, perpendicular = √12 cm.
<h3>by formula,</h3>→ h^2 = p^2 + b^2
→ (x)^2 = (√12)^2 + (√30)^2
→ x^2 = 12 + 30
→ x^2 = 42
→ x = √42
→ x = 6.480...
→ x = 6.5 cm. (approx)
<h3>___________________________</h3>(b) hypotenuse = √300 cm, base = √200 cm,perpendicular = x cm.
<h3>by formula,</h3>→ h^2 = p^2 + b^2
→ (√300)^2 = (x)^2 + (√200)^2
→ 300 = x^2 + 200
→ x^2 = 300 – 200
→ x^2 = 100
→ x = √100
→ x= 10 cm.
<h3>___________________________</h3>(c) hypotenuse = √66 cm, base = √17 cm,perpendicular = x cm.
<h3>by formula,</h3>→ h^2 = p^2 + b^2
→ (√66)^2 = (x)^2 + (√17)^2
→ 66 = x^2 + 17
→ x^2 = 66 – 17
→ x^2 = 49
→ x = √49
→ x = 7 cm.
<h3>___________________________</h3>(d) hypotenuse = x cm, base = 5√12 cm,perpendicular = 2√3 cm.
<h3>by formula,</h3>→ h^2 = p^2 + b^2
→ (x)^2 = (2√3)^2 + (5√12)^2
→ x^2 = 12 + 50
→ x^2 = 62
→ x = √62
→ x = 7.874...
→ x = 7.9 cm. (approx)
<h3>___________________________</h3><h3>Hope it helps you!!</h3>