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galben [10]
3 years ago
7

Prove that root 7 is an irrational number.

Mathematics
2 answers:
HACTEHA [7]3 years ago
8 0

Answer:

it is an irrational number and here is why

Step-by-step explanation:

So think of square root as it's answer is something that you you multiply its self by its self and you get that answer. Ex: 8 x 8 = 64 square root of 64 is 8. So in that case there is nothing you can exactly multiply by itself to get 7 so in that case it's a decimal or an irrational number.

HOPE THIS HELPS!

s344n2d4d5 [400]3 years ago
4 0

Answer: Root 7 would equal 2.64575131106 and would go on forever.

Step-by-step explanation: It isn't one of the perfect squares. For example, the first 10 perfect square are 1, 4, 9, 16, 25, 36, 49, 64, 81, and 100.

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Answer:

Option 3

Step-by-step explanation:

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The word "bisector" indicates that AB is cut into two equal parts, which allows us to make that claim.

<AXC≅<BXC because they are both equal to 90 degrees. This is because perpendicular means that the two lines are meeting at a 90-degree angle. Since both of them are 90 degrees, they are congruent.

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3 years ago
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