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4 years ago

7

a coil of wire that is carrying a current and produces a magnetic field is a. a galvanometer. b. a solenoid. c. a magnetic domai

n. d. an electric motor.

1 answer:

victus00 [196]4 years ago

6 0

It is a solenoid.

The coil of wire looks like a spring and inside of it is a magnetic field

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A water slide is constructed so that swimmers, starting from rest at the top of the slide, leave the end of the slide traveling

Kay [80]

Answer:

4.93 m

Explanation:

According to the question, the computation of the height is shown below:

But before that first we need to find out the speed which is shown below:

As we know that

$Speed = \frac{Distance}{Time}$

$Speed = \frac{5}{0.504}$

= 9.92 m/s

Now

$v^2 - u^2 = 2\times g\times h$

$9.92^2 = 2\times 9.98 \times h$

98.4064 = 19.96 × height

So, the height is 4.93 m

We simply applied the above formulas so that the height i.e H could arrive

8 0

4 years ago

A car is traveling north at 17.7m/s After 12 s its velocity is 14.1m/s in the same direction. Find the magnitude and direction o

Nat2105 [25]

The car is initially traveling north at 17.7 m/s, and after 12 s, its velocity is 14.1 m/s, still due north. This means that the direction of the car has not changed, so we can already say that the direction of the acceleration is north (if the magnitude of the acceleration is positive) or south (if the magnitude of the acceleration is negative).

To find the magnitude of the average acceleration, we must calculate the ratio between the change in velocity and the time taken:

$a=\frac{v_f -v_i}{t}=\frac{14.1 m/s-17.7 m/s}{12 s}=-0.3 m/s^2$

Since the acceleration is negative, it means it is in the opposite direction to the motion of the car, therefore south. Therefore, the correct answer is

b) 0.30 m/s2, south

7 0

3 years ago

An object is launched at a velocity of 20 m/s in a direction making an angle of 25° upward with the horizontal.

Hitman42 [59]

Answer:

(a) max. height = 3.641 m

(b) flight time = 1.723 s

(c) horizontal range = 31.235 m

(d) impact velocity = 20 m/s

Above values have been given to third decimal. Adjust significant figures to suit accuracy required.

Explanation:

This problem requires the use of kinematics equations

v1^2-v0^2=2aS .............(1)

v1.t + at^2/2 = S ............(2)

where

v0=initial velocity

v1=final velocity

a=acceleration

S=distance travelled

SI units and degrees will be used throughout

Let

theta = angle of elevation = 25 degrees above horizontal

v=initial velocity at 25 degrees elevation in m/s

a = g = -9.81 = acceleration due to gravity (downwards)

(a) Maximum height

Consider vertical direction,

v0 = v sin(theta) = 8.452 m/s

To find maximum height, we find the distance travelled when vertical velocity = 0, i.e. v1=0,

solve for S in equation (1)

v1^2 - v0^2 = 2aS

S = (v1^2-v0^2)/2g = (0-8.452^2)/(2*(-9.81)) = 3.641 m/s

(b) total flight time

We solve for the time t when the vertical height of the object is AGAIN = 0.

Using equation (2) for vertical direction,

v0*t + at^2/2 = S substitute values

8.452*t + (-9.81)t^2 = 3.641

Solve for t in the above quadratic equation to get t=0, or t=1.723 s.

So time for the flight = 1.723 s

(c) Horiontal range

We know the horizontal velocity is constant (neglect air resistance) at

vh = v*cos(theta) = 25*cos(25) = 18.126 m/s

Time of flight = 1.723 s

Horizontal range = 18.126 m/s * 1.723 s = 31.235 m

(d) Magnitude of object on hitting ground, Vfinal

By symmetry of the trajectory, Vfinal = v = 20, or

Vfinal = sqrt(v0^2+vh^2) = sqrt(8.452^2+18.126^2) = 20 m/s

7 0

4 years ago

Starting from rest, your friend dives from a high cliff into a deep lake below, yelling in excitement at the thrill of free-fall

Olegator [25]

Answer:

2 seconds

Explanation:

f = Frequency of yell = 919 Hz

$\Delta f$ = Shifted frequency = 55.9 Hz

v = Speed of sound in air = 342 m/s

$v_r$ = Velocity of friend

a = Acceleration due to gravity = 9.81 m/s²

From the Doppler shift formula we have

$\dfrac{f+\Delta f}{f}=\dfrac{v}{v-v_r}\\\Rightarrow v_r=v-\dfrac{vf}{f+\Delta f}\\\Rightarrow v_r=342-\dfrac{342\times 919}{919+55.9}\\\Rightarrow v_r=19.61\ m/s$

The velocity of the my friend is 19.61 m/s

$v=u+at\\\Rightarrow t=\dfrac{v-u}{a}\\\Rightarrow t=\dfrac{19.61-0}{9.8}\\\Rightarrow t=2\ s$

The time my friend is in the air is 2 seconds

7 0

3 years ago

Oxidation and reduction are processes which

Firlakuza [10]

Answer:

Oxidation is increase in oxidation number while reduction is decrease in oxidation number.Redox is change in oxidation number.

4 0

3 years ago