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vladimir1956 [14]
3 years ago
8

A tourist in France wants to visit 10 different cities. If the route is randomly selected, what is the probability that she will

visit the cities in alphabetical order?
Mathematics
1 answer:
ella [17]3 years ago
6 0

Answer:

1/3628800

Step-by-step explanation:

This question requires that we calculate

1/number of permutations of 10 cities

= P(n,k) = n!/(n-k)!

We have

n = 10

k = 10

= 10!/(10-10)!

= 10!

number of permutations of 10 cities 10! This Is equal to 3,628,800

From this answer we the probability of doing a random tour of these 10 different cities in alphabetical order.

And this is

= 1/3,628,800

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