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Elena-2011 [213]
3 years ago
12

A 60-yard long drawbridge has one end at ground level. The other end is initially at an incline of 5°. During one stage of the d

rawbridge's motion, the raised end is 11 yards above the ground. What is the incline of the drawbridge to the nearest hundredth
Mathematics
1 answer:
AVprozaik [17]3 years ago
7 0
The drawbridge will be at an incline of 10.56 degrees. That is 5.56 degrees more than it's initial incline of 5 degrees.

If you draw a picture of this situation, you will see that you can write a sine ratio with the 11 and 60 (opposite over hypotenuse)

sin(x) = 11/60  Solve the equation for x

x = 10.56
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Answer:

a is true and becomes complimentary as they both add up to 90 degree.

b. is true it is the only vertical angle group. As points AE, and BD cross and create these angles.

c is supplementary as both 3,4 together add up to 180

but each of these do not fit other description, as 5,1 would be also supplementary if 2 was in that group.

Step-by-step explanation:

Points 3, 4 as a group and 3,2,1 as a group and 2,1,5 as a group are each supplementary as each group add up to 180 degree. 1,5 on its own is not supplementary

Points 2 is complimentary on its own and also 1,5 combined are complimentary so this is true and  1,5 on its own as a group is complimentary.

Points 3,5 become vertical angles as a group.

Angles A:B + D:E are also vertical angles this shows points 1,2 and 4 as a group of vertical angles.

Vertical Angles are the angles opposite each other when two lines cross. "Vertical" in this case means they share the same Vertex (corner point), not the usual meaning of up-down

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If a quadrilateral has exactly 2 lines of symmetry, and both are angle bisectors, then which statement would be true?
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Answer:

the figure could be a rhombus because the 2 lines of symmetry bisect the angles

Step-by-step explanation:

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Answer:

1709.92cm^3

Step-by-step explanation:

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