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den301095 [7]
3 years ago
5

Logical variables: Running late? Complete the tunction RunningLate such that the logical variable on Time is true if no Traffic

is true and gasEmpty is false. Ex >> n°Traffic = true ; >> gasEmpty-false; >onTime - Runninglate(noTraffic,gasEmpty) logical Your Function B Save C Reset EE MATLAB Documentation 1 function onTime - RunningLate (noTraffic,gasEmpty) 2 % complete the logical expression to the right of . using the variables n°Traffic and gasEmpty 4 onTime - 6 end Code to call your function C Reset 1 noTraffic true; gasEmpty true; 2 onTime-Runninglate(noTraffic, gasEmpty)
Engineering
1 answer:
MrMuchimi3 years ago
8 0

Answer:

"""""""""""""""""""""""""In case of any doubt please comment""""""""""""""""""""""""

Now we need the function to return true if noTraffic= true and gasEmpty = false;

NOTE:"Rest in all cases it should return false;

Now for that to happen we use and- operator (x & y) it returns true only when both x and y are true.

but we need true when gasEmpty = false. For that we will use not function on gasEmpty.

Now the function will return true (1) only when noTraffic = true and gasEmpty = false. Rest in all case it will return false (0)

​​​​​​​

function onTime = RunningLate (noTraffic, gasEmpty)

onTime = ( (noTraffic) & not(gasEmpty) )

end

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a ten station assembly machine has ideal cycle time of 6 sec. the fraction defect rate at each station 0.005 and defect always j
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Answer:

T_{P}=(2.6667)(10^{-3})h

Explanation:

Let's write the equation of the production rate for the assembly machine :

T_{P}=T_{C}+(n).(m).(p).(T_{D})

Where T_{P} is the production rate for the assembly machine.

Where T_{C} is the ideal cycle time

Where n is the number of stations.

Where m is the number stations that get jam when the defect occurs.

Where p is the defect rate at each station.

And where T_{D} is the average downtime per breakdown

We are looking for the hourly production rate ⇒

1h=60min\\1min=60s ⇒

1h=3600s ⇒

6s=\frac{(6s)(1h)}{(3600s)}= \frac{1}{600}h

60min=1h ⇒

1.2min=\frac{(1.2min)(1h)}{(60min)}=0.02h

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3 0
3 years ago
A square-thread power screw has a major diameter of 32 mm and a pitch of 4 mm with single threads, and it is used to raise a loa
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Answer:

54mm.

Explanation:

So, we are given the following data or parameters or information that is going to assist in solving this type of question efficiently;

=> "A square-thread power screw has a major diameter of 32 mm"

=> "a pitch of 4 mm with single threads"

=> " and it is used to raise a load putting a force of 6.5 kN on the screw."

=> The coefficient of friction for both the collar and screw is .08."

=> "If the torque from the motored used to raise the load is limited to 26 N×M."

Step one: determine the lead angle. The lead angle can be calculated by using the formula below;

Lead angle = Tan^- (bg × T/ Jh × π ).

=> Jh = J - T/ 2. = 32 - 4/2. = 30mm.

Lead angle = Tan^- { 1 × 4/ π × 30} = 2.43°.

Step two: determine the Torque required to against thread friction.

Starting from; phi = tan^-1 ( 0.08) = 4.57°.

Torque required to against thread friction = W × Jh/2 × tan (lead angle + phi).

Torque required to against thread friction =( 6500 × 30/2) × tan ( 2.43° + 4.57°). = 11971.49Nmm.

Step three: determine the Torque required to against collar friction.

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Step four = determine the mean collar friction.

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