All categories

3 years ago

What competitive strategy was used by Regal Marine?

Engineering

1 answer:

lora16 [44]3 years ago

7 0

Answer:

Regal Marine uses a strategy of product differentiation, which constantly introduces new products with new innovations and new styling to stay competitive in the luxury performance boat market.

You might be interested in

Calculate the De-Broglie wavelength for electron accelerated across a potential of 10V, 100V, 1000V, and 10kV respectively. Whic

Arlecino [84]

Answer:

a) $\lambda=3.87 \r A$

b) $\lambda=1.23 \r A$

c) $\lambda=0.387 \r A$

d) $\lambda=0.123 \r A$

Explanation:

We know that the kinetic energy can be expressed in terms of momentum (p= mv):

$K=\frac{p^{2}}{2m}$

p is the momentum
m is the mass of the particle

So, the momentum will be:

$p=\sqrt{2mK}$ (1)

We can use the energy conservation to relate K and the electric potential energy. We assume that all potential energy becomes kinetic energy. Therefore:

$K=q_{e}V$ (2)

a) If V=10 [V], K will be:

$K=1.6*10^{-19}*10=1.6*10^{-18}[J]$

We can find the momentum using the equation (1)

$p=\sqrt{2*9.1 x 10^{-31}*1.6*10^{-18}}=1.71*10^{-24}[kg*m*s^{-1}]$

The De-Broglie wavelength equation is given by:

$\lambda=\frac{h}{p}$ (3)

h is the Plank constant ( $h=6.626 x 10^{-34} [J*s]$ )

$\lambda=\frac{6.626 x 10^{-34}}{1.71*10^{-24}}=3.87*10^{-10}[m]=3.87 \r A$

b) If V=100 [V], using the same analyze, the De-Broglie wavelength will be:

$K=1.6*10^{-19}*100=1.6*10^{-17}[J]$

$p=\sqrt{2*9.1 x 10^{-31}*1.6*10^{-17}}=5.39*10^{-24}[kg*m*s^{-1}]$

$\lambda=\frac{6.626 x 10^{-34}}{5.39*10^{-24}}=1.23*10^{-10}[m]=1.23 \r A$

c) V=1000 [V]

$K=1.6*10^{-19}*100=1.6*10^{-16}[J]$

$p=\sqrt{2*9.1 x 10^{-31}*1.6*10^{-16}}=1.71*10^{-23}[kg*m*s^{-1}]$

$\lambda=\frac{6.626 x 10^{-34}}{1.71*10^{-23}}=3.87*10^{-11}[m]=0.387 \r A$

d) V=10000 [V]

$K=1.6*10^{-19}*100=1.6*10^{-15}[J]$

$p=\sqrt{2*9.1 x 10^{-31}*1.6*10^{-15}}=5.40*10^{-23}[kg*m*s^{-1}]$

$\lambda=\frac{6.626 x 10^{-34}}{5.40*10^{-23}}=1.23*10^{-11}[m]=0.123 \r A$

The fringe spacing interference is proportional to the wavelength, so in our case, the larger fringe spacing occurs when voltage is 10 V, here λ = 3.87 angstroms.

I hope it helps you!

5 0

3 years ago

Why do we need the metering devices? List the basic types.

Xelga [282]

Answer:para comprar terreno por ejemplo

to buy land for example

Explanation: meter, centimeter

4 0

3 years ago

What is the best machine to measure the size of cables?

nadya68 [22]

When operating, an instrument measures the total capacitance in the cable and then uses the cable's Mutual Capacitance Coefficient to calculate the cable's length. Capacitance-based measurement instruments can typically measure the length accurate to about 4 percent to 5 percent. i even gave an explanation if u wanted to see how it measures

6 0

3 years ago

A pressure gage at the inlet to a gas compressor indicates that the gage pressure is 40.0 kPa. Atmospheric pressure is 1.01 bar.

bonufazy [111]

Answer:

Given

inlet Pga =40kpa = 40000pa

Patm=1.01bar = 1.01 x 100000pa =101000pa

exit Pab= 6.5 (inlet Pab)

But generally, Pab = Patm + Pga

1. the absolute pressure of the gas at the inlet, inlet Pab?

inlet Pab = Patm + inlet Pga

= 101000pa + 40000pa = 141kpa

the absolute pressure of the gas at the inlet, inlet Pab = 141kpa

2. the gage pressure of the gas at the exit? exit Pga?

exit Pab = Patm + exit Pga

exit Pga = exit Pab - Patm

= (6.5 x 141kpa) - 101kpa

= 815.5kpa

the gage pressure of the gas at the exit exit Pga=815.5kpa

5 0

3 years ago

TWO SENTENCES!!!! What are the benefits of working in an engineering team?

Vlad [161]

1. You get to build cool things for places like nasa.
2. You get paid very well

Hope this helps

7 0

3 years ago

Read 2 more answers