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Savatey [412]
2 years ago
6

-3/2(x-2) +1=4 Justify your steps

Mathematics
1 answer:
sattari [20]2 years ago
8 0

Answer:

x=0

Step-by-step explanation:

-3/2(x-2) +1=4

Subtract 1 from each side by the subtraction property of equality

-3/2(x-2) +1-1=4-1

-3/2 (x-2) = 3

Multiply each side by -2/3 by the multiplication property of equality

-2/3 * -3/2 (x-2) = 3 *-2/3

Simplify

x-2 = -2

Add 2 to each side by the addition property  of equality

x-2+2 = -2+2

x=0

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Solve <br> 6r + 7 = 13 + 7r
Firdavs [7]

Answer:

r = -6

Step-by-step explanation:

6r + 7 = 13 + 7r

-6r both sides

7 = 13 + r

-7 both sides

r + 6 = 0

-6 both sides

r = -6

8 0
3 years ago
Read 2 more answers
Suppose that your business is operating at the 4.5-Sigma quality level. If projects have an average improvement rate of 50% annu
Luda [366]

Answer:

  11.75 years

Step-by-step explanation:

If we ignore the fact that "6-sigma" quality means the error rate corresponds to about -4.5σ (3.4 ppm) and simply go with ...

  P(z ≤ -6) ≈ 9.86588×10^-10

and

  P(z ≤ -4.5) ≈ 3.39767×10^-6

the ratio of these error rates is about 0.000290372. We're multiplying the error rate by 0.5 each year, so we want to find the power of 0.50 that gives this value:

  0.50^t = 0.000290372

  t·log(0.50) = log(0.00290372) . . . . take logarithms

  t = log(0.000290372)/log(0.50) ≈ -3.537045/-0.301030

  t ≈ 11.75

It will take about 11.75 years to achieve Six Sigma quality (0.99 ppb error rate).

_____

<em>Comment on Six Sigma</em>

A 3.4 ppm error rate is customarily associated with "Six Sigma" quality. It assumes that the process may have an offset from the mean of up to 1.5 sigma, so the "six sigma" error rate is P(z ≤ (1.5 -6)) = P(z ≤ -4.5) ≈ 3.4·10^-6.

Using that same criteria for the "4.5-Sigma" quality level, we find that error rate to be P(z ≤ (1.5 -4.5)) = P(z ≤ -3) ≈ 1.35·10^-3.

Then the improvement ratio needs to be only 0.00251699, and it will take only about ...

  t ≈ log(0.00251699)/log(0.5) ≈ 8.6 . . . . years

5 0
3 years ago
Latoya had a large collection of basketball cards. she gave half to her friend,Erin. And 1/4 to her brother. She now has 75 card
Kipish [7]

For this case, the first thing we must do is define variables.

We have then:

x: initial amount of cards

We now write the equation that models the problem:

x - (\frac{1}{2}) x - (\frac{1}{4}) x = 75

(\frac{1}{4}) x = 75\\x = 75 * 4\\x = 300

Therefore, the initial amount of cards is 300

Answer:

Latoya had 300 cards at the beginning

5 0
3 years ago
Read 2 more answers
xYou volunteer to help drive children at a charity event to the​ zoo, but you can fit only 6 of the 16 children present in your
brilliants [131]

There are 8008 groups in total, in other to drive the children

<h3>How to determine the number of groups?</h3>

From the question, we have

  • Total number of children, n = 16
  • Numbers to children at once, r = 6

The number of group of children that could be carried at once is calculated using the following combination formula

Total = ⁿCᵣ

Where

n = 16 and r = 6

Substitute the known values in the above equation

Total = ¹⁶C₆

Apply the combination formula

ⁿCᵣ = n!/(n - r)!r!

So, we have

Total = 16!/10!6!

Evaluate

Total = 8008

Hence, the number of groups is 8008

Read more about combination at

brainly.com/question/11732255

#SPJ1

8 0
1 year ago
Answer the ones you know
vladimir2022 [97]
For question 2 it is 15

Because: 4 time 6 is 24 and then you minus 9 which is 15

So there you have it the answer is 15





8 0
3 years ago
Read 2 more answers
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