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pishuonlain [190]
2 years ago
7

The Pythagorean Theorem can be used to find the distance between points (3, 2) and (6, 4). Select all the points that could be t

he third vertex in the
triangle.

(0,0)
(3,4)
(3,6)
(4.5,3)
(6,2)
Mathematics
1 answer:
german2 years ago
4 0

(3,4) and (6,2) could be vertices of a right triangle with (6,4) and (3,2)

(0,0) is on the same line as (6,4) and (3,2) so it doesn't even form a triangle, much less a right triangle.

(3,6) forms a scalene isosceles triangle, but not a right triangle  It's a 4-sqr13-sqr13 triangle

(4.5,3) also forms an obtuse isosceles triangle, but not a right triangle  It's a sqr13 - sqr3.25 - sqr3.25 triangle

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Please help ASAP!! I'm really stuck on this question.
Neko [114]

Answer:

<W,<J, <K

Step-by-step explanation:


3 0
3 years ago
Solve for x in the given interval.<br><br> sec x= -2√3/3, for π/2 ≤x≤π
drek231 [11]

Answer:

b. x=\frac{5\pi}{6}

Step-by-step explanation:

The given function is

\sec x=-\frac{2\sqrt{3} }{3},\:\:for\:\:\frac{\pi}{2}\le x \le \pi

Recall that the reciprocal of the cosine ratio is the secant ratio.

This implies that;

\frac{1}{\cos x}=-\frac{2\sqrt{3} }{3}

\Rightarrow \cos x=-\frac{3}{2\sqrt{3} }

\Rightarrow \cos x=-\frac{\sqrt{3}}{2}

We take the inverse cosine of both sides to obtain;

x=\cos^{-1}(-\frac{\sqrt{3}}{2})

x=\frac{5\pi}{6}

4 0
3 years ago
Suppose we have a right triangle with legs of length a and b and hypotenuse of length c. Suppose b=3 and c=5. Then a= , For the
ANTONII [103]

Answer:

Length of right-angle  triangle 'a' = 4

b)

<u><em></em></u>sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}<u><em></em></u>

<u><em></em></u>cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}<u><em></em></u>

<u><em></em></u>tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}<u><em></em></u>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given  b = 3 and hypotenuse c = 5

Given ΔABC  is a right angle triangle

By using pythagoras theorem

        c² = a² + b²

  ⇒ a² = c² - b²

 ⇒  a² = 5²-3²

          =25 - 9

      a² = 16

⇒   a = √16 = 4

The sides of right angle triangle  a = 4 ,b = 3 and c = 5

<u><em>Step(ii):-</em></u>

<u><em></em></u>sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}<u><em></em></u>

<u><em></em></u>cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}<u><em></em></u>

<u><em></em></u>tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}<u><em></em></u>

7 0
2 years ago
Example 2
PIT_PIT [208]

Answer: (a) 314.2cm², (b) 157.1cm², (c) 78.55cm² (e) 6.77

Step-by-step explanation: (a)  Area of the circle with radius of 10 cm = πr²

                                                                          = 3.142 × 10 × 10

                                                                          = 3.142 × 100

                                                                          = 314.2cm²

The formula                                                       = πr²

(b)  Area of the half of a circle known as semicircle

                                                                         = πr²/2

                                                                         = 3.142 ×10 × 10/2

                                                                         = 3.142 × 50

                                                                         = 157.1cm²

The formula                                                      = πr²/2

(c)  A quarter of a circle is called quadrant

                                                            = πr²/4

                                                            = 3.142 × 10 × 10/4

                                                            = 314.2/4

                                                            = 78.55cm²

The formula is written thus = πr²/4, which implies that the circle is divided into 4 unit

(d) The conjecture about how to determine the area of the sector is

Formula of a sector = ∅/360(πr²)

<u>Information</u>

The arc  cant be 60°, therefore information incomplete.

(e) Area of the sector with the angle AOB of 60° = 24.

To find the radius of the angle, make v the subject of the formula from the formula.

Sector area = πr²∅/360°

equate formula to 24.

Therefore πr²∅/360° = 24

Multiply through by360° to make it a linear expression

It now becomes πr²∅ =24× 360°

                                                     r² = 24  x 360/π × ∅°

                                                     r² = 24 × 360° /3.142 × 60°

                                                     r² = 3,640/188.52

                                                     r² = 45.8

To find r , we take the square root of both side by applying laws of indicies

                                    Therefore r = √45 .8

                                                      r = 6.77

(f)   General formula = ∅°/360° × (πr²)

angle substended at centre by the arc = x°

assuming the radius of the circle = ycm, Therefore,  area of the sector = { ∅°/360° × πy² }

                                                     

                                                   

8 0
3 years ago
A group of college students are going to a lake house for the weekend and plan on renting small cars and large cars to make the
dangina [55]

The system of equations that could be used to determine the number of small cars rented and the number of large cars rented is;

x + y = 10

x + y = 105x + 7y = 66

<h3>Simultaneous equation</h3>

  • Small car = 5 people
  • Large car = 7 people
  • Total cars = 10
  • Total number of people = 66

Let

Number of small cars rented = x

Number of large cars rented = y

x + y = 10

x + y = 105x + 7y = 66

Learn more about simultaneous equation:

brainly.com/question/16863577

#SPJ1

3 0
1 year ago
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