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tatiyna
3 years ago
10

Electric fields are MOST associated with ________.

Physics
1 answer:
alukav5142 [94]3 years ago
5 0
With each point in space
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A car comes to a bridge during a storm and finds the bridge washed out. The driver must get to the other side, so he decides to
Mrrafil [7]

Answer:

Explanation:

1 ) Let the initial horizontal velocity of car be v .

For vertical displacement

vertical displacement h = 21.3 - 2.3 = 19 m

Time taken to fall by 19 m be t

19 = 1/2 x 9.8 t² ( initial downward velocity is zero )

t = 1.97 s

This is also the time taken to cover horizontal displacement of 54 m which is width of river .

horizontal speed v = 54 / 1.97 m /s

v = 27.41 m /s

2 )

At the time of landing on other side , car will have both vertical and horizontal speed .

vertical speed

v = u + gt

= 0 + 9.8 x 1.97 = 19.31 m /s

horizontal speed will remain same as  the initial speed = 27.41 m /s

Resultant speed = √ ( 27.41² + 19.31² )

= √ ( 751.3 + 372.87)

= 33.52 m /s

3 0
3 years ago
Is the time in Tennessee the same as florida
geniusboy [140]
I would say the same thing as the first answer
5 0
4 years ago
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An air bubble at the bottom of a lake 36.0 m deep has a volume of 1.22 cm^3. If the temperature at the bottom is 5.9°C and at th
AlexFokin [52]

Answer:

volume of the bubble just before it reaches the surface is 5.71 cm³

Explanation:

given data

depth h = 36 m

volume v2 = 1.22 cm³ = 1.22 × 10^{-6} m³

temperature bottom t2 = 5.9°C = 278.9 K

temperature top  t1 = 16.0°C = 289 K

to find out

what is the volume of the bubble just before it reaches the surface

solution

we know at top atmospheric pressure is about P1 = 10^{5} Pa

so pressure at bottom P2 = pressure at top + ρ×g×h

here ρ is density and h is height and g is 9.8 m/s²

so

pressure at bottom P2 = 10^{5} + 1000 × 9.8 ×36

pressure at bottom P2 =4.52 × 10^{5}  Pa

so from gas law

\frac{P1*V1}{t1} = \frac{P2*V2}{t2}

here p is pressure and v is volume and t is temperature

so put here value and find v1

\frac{10^{5}*V1}{289} = \frac{4.52*10^{5}*1.22}{278.9}

V1 = 5.71 cm³

volume of the bubble just before it reaches the surface is 5.71 cm³

6 0
3 years ago
A Laboratory Technician was examining a blood sample from a patient. He found a rare parasite that would cause the nausea and vo
Paraphin [41]

Answer:A is the answer

Explanation: I know it's late but here you go

5 0
3 years ago
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1kg slab of concrete loses 12,000j of heat when it cools from 30 Celsius to 26 Celsius. Determine the specific heat capacity of
OleMash [197]

The specific heat capacity of concrete is 3.0 J/(g^{\circ}C)

Explanation:

When a certain amount of energy Q is supplied/given off to/from a sample of substance with mass m, the temperature of the substance increases/decreases by an amount \Delta T, according to the equation

Q=mC_s \Delta T

where

m is the mass of the substance

C_s is the specific heat capacity of the substance

\Delta T is the change in temperature of the substance

In this problem, we have:

m = 1 kg = 1000 g is the mass of the concrete slab

Q = -12,000 J is the amount of energy lost by the slab

\Delta T = 30-26= -4^{\circ}C is the change in temperature of the slab

Solving the equation for C_s, we find the specific heat capacity of concrete:

C_s = \frac{Q}{m \Delta T}=\frac{-12,000}{(1000)(-4)}=3.0 J/(g^{\circ}C)

Learn more about specific heat capacity:

brainly.com/question/3032746

brainly.com/question/4759369

#LearnwithBrainly

3 0
3 years ago
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