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e-lub [12.9K]
3 years ago
8

What is the pressure at the bottom of a 2.50 m deep pool of water?

Physics
1 answer:
Grace [21]3 years ago
8 0

Answer:

Pressure = Density x Gravity acceleration x Height

Density of water = 1000 Kgm^-3

Gravity acceleration = 9.8 ms^-2

So it is 4.50.

Hope this helps and please mark me brainliest!

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What's the opposite of vaporization
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Condensation. Remember, Vaporization happens when energy is taken in (enfothermic) the opposite will be the process that releases energy ( exothermic) which will be condensation. Put ice in a glass of water. the ice melts, taking in energy from the water in the glass, which in turn takes heat energy away from the vapor in the surrounding air, thus causing the water vapor in the air to condense.
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3 years ago
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What is a good topic sentence when writing about what happens to your body if you drink a Coke ?
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Based on research by health writer Wade Meredith, it explains that a 330ml can of Coca Cola contains so much sugar, your body should vomit - but the phosphoric acid "cuts the flavor", helping you keep the liquid down.

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8 0
3 years ago
A student drops two metallic objects into a 120-g steel container holding 150 g of water at 25°C. One object is a 206-g cube of
spayn [35]

Answer:

Mass of the aluminium chunk = 278.51 g

Explanation:

For an isolated system as given the energy lost and gains in the system will be zero therefore sum of all transfer of energy will be zero,as the temperature will also remain same

A specific heat formula is given as                  

Energy Change = Mass of liquid x Specific Heat Capacity x Change in temperature

                                       Q =  m×c×ΔT

                        Heat gain by aluminium + heat lost by copper  = 0    (1)

For Aluminium:

      Q = m\times0.897\frac{J}{g.k}\times(25-5)

      Q = m x 17.94 joule

For Copper:

Q= 206g\times0.385\frac{J}{g.k} \times(88-25)

       Q= 4996.53 Joule

from eq 1

     m x 17.94 = 4996.53

     mass of aluminium = \frac{4996.53}{17.94} g

    Mass of the aluminium chunk = 278.51 g

                         

3 0
3 years ago
A pickup truck and a hatchback car start at the same position. If the truck is moving at a constant 33.2m/s and the hatchback ca
love history [14]

Answer:

The pickup truck and hatchback will meet again at 440.896 m

Explanation:

Let us assume that both vehicles are at origin at the start means initial position is zero i.e. s_{o} = 0. Both the vehicles will cross each other at same time so we will make equations for both and will solve for time.

Truck:

v_{i} = 33.2 m/s, a = 0 (since the velocity is constant), s_{o} = 0

Using s =s_{o}+v_{i}t+1/2at^{2}

s = 33.2t .......... eq (1)

Hatchback:

a=5m/s^{2}, v_{i} = 0 m/s (since initial velocity is zero), s_{o} = 0

Using s =s_{o}+v_{i}t+1/2at^{2}

putting in the data we will get

s=(1/2)(5)t^{2}

now putting 's' value from eq (1)

2.5t^{2}-33.2t=0

which will give,

t = 13.28 s

so both vehicles will meet up gain after 13.28 sec.

putting t = 13.28 in eq (1) will give

s = 440.896 m

So, both vehicles will meet up again at 440.896 m.

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lakkis [162]

Answer:

TRUE.

Explanation:

YES IT EFFECTS.

IT MAY HELP YOU.

7 0
3 years ago
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