3 years ago

Dan has 18 chocolates. Lee has 14 chocolates. How many fewer chocolates does Lee have?

Mathematics

2 answers:

artcher [175]3 years ago

8 0

Answer:

4 Fewer Chocolates

Step-by-step explanation:

18-14=4

liberstina [14]3 years ago

3 0

Answer:

Step-by-step explanation:

Dan's Chocolates = x

Lee's Chocolates = y

x - y = ?

18 - 14 = 4

Lee has 4 few chocolates than Dan.

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