Question

A helicopter is ascending vertically with a speed of 5.10m/s. At a height of 105 m above the Earth, a package is dropped from a window. How much time does it take for the package to reach the ground?

Answer 1

Answer:

The time taken for the package to reach the ground is 20.6s

Explanation:

Given that the formula of distance is D = S×T where S represents soeed and T is time. So you have to substitute the following values into the formula :

$distance = speed \times time$

$let \: distance = 105 \\ let \: speed = 5.10$

$105 = 5.1 \times t$

$5.1t = 105$

$t = 105 \div 5.1$

$t = 20.6 \: second \: (3s.f)$