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avanturin [10]
3 years ago
11

Help me please....

Physics
2 answers:
snow_tiger [21]3 years ago
6 0

Answer:

1) Time period

2) amplitude

3) Hertz or hz

4) Noise

5) frequency

6) infrasonic and ultrasonic

7) solid liquid and gas

8) A man

9) energy

10)1 vibration per minute

yuradex [85]3 years ago
6 0

Answer: Time taken by an object to complete one oscillation is called time PERIOD.

Explanation:Hope this helps!! Brainlist?plz I need it

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the answer is d I'm pretty sure

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What is the half-life of an isotope if after 30 days you have 31.25 g remaining from a 250 g beginning sample size?
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Answer:The time required for half of the original population of radioactive atoms to decay is called the half-life. The relationship between the half-life, T1/2, and the decay constant is given by T1/2 = 0.693/λ.

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Based on the graph of velocity over time, which could be the initial velocity and the final velocity for this graph?
dolphi86 [110]
The graph is showing a constant velocity as the line is horizontal. The initial speed is equal to the final speed as there is no changing in acceleration. The second statement is the correct statement

Initial = 2.5 m/s
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3 0
3 years ago
Read 2 more answers
Suppose you now take the ball and using a bat, pop it straight up into the air with a hang-time of 5.00 s (the hang time is how
dolphi86 [110]

Answer:

<h3>30.66m</h3>

Explanation:

Using the equation of motion formula S = ut + \frac{1}{2}gt^2 where;

S is the height to which the ball rises

u is the initial velocity of the ball = 0m/s

a is the acceleration due to gravity = 9.81m/s²

t is the time taken by the ball in air = 5.0s

Note that the  time to rise to the peak is one-half the total hang-time = 5.0/2 = 2.5s

Substituting the given parameters into the formula above to get S:

S = ut + \frac{1}{2}gt^2\\\\S = 0(2.5)+ \frac{1}{2}(9.81)(2.5)^2\\\\S = 0+\frac{1}{2}(9.81)\times 6.25 \\\\S = \frac{61.3125}{2}\\ \\S = 30.65625m\\\\S \approx 30.66m

This means that the ball rises 30.66m before it reaches its peak.

8 0
3 years ago
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