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Nezavi [6.7K]
3 years ago
6

Can someone help me with this?

Mathematics
1 answer:
Elena L [17]3 years ago
3 0
A. Robert purchased a 36-inch piece of wood
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Lenox ironed 1/4 of the shirts over the weekend. she plans to split the remainder of the work eqaully over the next 5 evenings?
Anettt [7]
A. If she completed 1/4, 3/4 are still left to be done over 5 days.
To find out how much per day, divide 3/4 by 5 (multiply the first number by the reciprocal of the second).
3/4*1/5= 3/20.

Final answer: 3/20

b. If she irons 3/20 a day, she should iron 6/20 or 3/10 over the course of two days, Thursday and Friday. 3/10 of 40 is 40*0.3= 12

Final answer: 12 shirts
3 0
3 years ago
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"Which ranges describe the cluster in the scatter plot?
Minchanka [31]
A.between 8 and 10 years of age,
<span>C.between 10 and 12 years of age

</span>

7 0
3 years ago
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The French Club is sponsoring a bake sale. If their goal is to raise at least $140, how many pastries must they sell at $3.50 ea
weeeeeb [17]

Let x be the number of pastries they must sell.

$3.50x≥140

This inequality states that for the number of pastries at 3.50 dollars each must be greater than or equal to 140. Solve for x.

3 0
3 years ago
Ken painted 14 meters of fencing in 1 hour. How many centimeters of fencing can he paint in 45 minutes?
Andrew [12]

Answer:

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Step-by-step explanation:

3 0
2 years ago
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The Carousel at Carowinds has 4 rings of horses. Fred is riding on the inner ring, which has a radius of 7 feet. Juan is riding
nikdorinn [45]

Answer:

Juan travel 31.4 feet farther than Fred in one rotation.

Step-by-step explanation:

In this problem we need to determine the change in linear position of Fred and Juan, whose formula is:

s=\theta \cdot r (Eq. 1)

Where:

r - Radius, measured in feet.

\theta - Angular arch, measured in radians.

s - Change in linear position, measured in feet.

If both makes one rotation in the carousel, we obtain the change in linear position of each player:

Fred (r = 7\,ft, \theta = 2\pi)

s= 2\pi\cdot (7\,ft)

s = (3.14)\cdot (7\,ft)

s = 21.98\,ft

Juan (r = 17\,ft, \theta = 2\pi)

s= 2\pi\cdot (17\,ft)

s = (3.14)\cdot (17\,ft)

s = 53.38\,ft

And the difference between both travelled distances is:

\Delta s = 53.38\,ft-21.98\,ft

\Delta s = 31.4\,ft

Juan travel 31.4 feet farther than Fred in one rotation.

4 0
3 years ago
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