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kari74 [83]
3 years ago
15

Which expression is equivalent to b^-2/ab^-3? Assume a doesn’t equal 0, b doesn’t equal 0

Mathematics
1 answer:
Alexandra [31]3 years ago
3 0

Answer:

Step-by-step explanation:

hello

\dfrac{b^{-2}}{ab^{-3}}=a^{-1}b^{-2+3}=a^{-1}b=\dfrac{b}{a}

hope this helps

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Can some one plz help i need to pass this lesson
Leona [35]

Answer:

Math, English

90 votes for History

40% votes for Math

Step-by-step explanation:

Eng 17

His 9

Math 24

Sci 10

Favorite subject is Math, and English since they have more votes

History is  9 out of 60 which is 9/60=.15  times 100 for percent 15%

15% of 600  is .15*600= 90

Math is 24 of 60 which is 24/60=.04 times 100 for percent 40%

3 0
2 years ago
Read 2 more answers
Write 87.5% as a fraction in simplest form
Len [333]
87 1/2 is the answer. hope it help.
6 0
3 years ago
part of the river she observed fell 1.68 millimeters per year for 1.5 years. Use the distributive property to calculate the exac
Alecsey [184]
1.68 mm per year for 1.5 years could be rewritten as 
(2.00-0.32) mm per year for 1.5 yrs.

Multiply:  (1.5 yrs)(2.00-0.32)(mm/yr) = 3 mm + 0.48 mm = 3.48 mm

This approach makes use of the distributive property of multiplication.
8 0
4 years ago
Write the equation of a piecewise function with a jump discontinuity at x =3. Then, determine which step of the 3-step test for
seraphim [82]

Answer:

Here's a possible example:

Step-by-step explanation:

f(x) =\begin{cases} x & \quad x < 3\\x+3 & \quad x \geq 3\\\end{cases}

Each piece is linear, so the pieces are continuous by themselves.

We need consider only the point at which the pieces meet (x = 3).

\displaystyle \lim_{x \longrightarrow 3^{-}} f(x) = \lim_{x \longrightarrow 3^{-}} x = 3\\\\\displaystyle \lim_{x \longrightarrow 3^{+}} f(x) = \lim_{x \longrightarrow 3^{+}} x+3 = 6\\\\f(3) = x + 3 = 6\\\\\displaystyle \lim_{x \longrightarrow 3^{-}} f(x) \neq f(3)

The left-hand limit does not equal ƒ(x), so there is a jump discontinuity at x =3.

5 0
3 years ago
What is the range of the function g(x) = 3x^2 - 6x + 3 when the domain is defined as the set of integers, x, such that 0&lt;=x&l
kakasveta [241]

Answer:

Range is  3 <= g(x) <= 27.

Step-by-step explanation:

The range  is the values of g(x) for the given domain.

When x = 0 g(x) = 3(0)^2 - 6(0) + 3 = 3.

When x = 4 g(x) = 3(4)^2 - 6(4) + 3 =  27.

6 0
3 years ago
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