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sveticcg [70]
3 years ago
9

Find the dimensions of the rectangular box with largest volume if the total surface area is given as 4 cm2. (Let x, y, and z be

the dimensions of the rectangular box).
Mathematics
1 answer:
Scorpion4ik [409]3 years ago
7 0

Answer:

The dimensions of the rectangular box, x = y = z = 0.817 cm

Step-by-step explanation:

Given;

total surface area of the rectangular box or cuboid = 4 cm²

A rectangular box with largest volume  is a cube.

The total surface area of a cube = 6 times  square of one edge length.

Let the edge length = given dimensions,  x, y, z

x = y = z

6x² = 4

x² = 4/6

x =\sqrt{\frac{4}{6} }\\\\ x = \frac{2}{\sqrt{6} } \ cm \ = 0.817 \ cm

Therefore, the dimensions of the rectangular box, x = y = z = 0.817 cm

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3 years ago
How to find the answer
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A village water tank measures 8m x5m x 3m. What is the capacity of the tank when full?
Bad White [126]

Answer:

Hence, the capacity of the tank when full is 120 cubic m.

Step-by-step explanation:

The measures of water tank is 8m x 5m x 3m.

The capacity of the tank when full is nothing but the capacity of the full tank which is the multiples of given dimensions.

The capacity of the tank when full is,

8m x 5m x 3m = 40 m^2 x 3m

                        = 120 m^3.

Hence, the capacity of the tank when full is 120 cubic m.

3 0
2 years ago
Patrick walks 9/10 mile to the gym. How far has he walked when he has covered 2/3 of the distance to the gym?
Margaret [11]
Uh I’d don’t know try to multiply them together to see what you get
3 0
2 years ago
A sample of 81 account balances of a credit company showed an average balance of $1,200 with a standard deviation of $126.
TEA [102]

Answer:

(a) Null Hypothesis, H_0 : \mu = $1,150  

    Alternate Hypothesis, H_A : \mu \neq $1,150

(b) The test statistic is 3.571.

(c) We conclude that the mean of all account balances is significantly different from $1,150.

Step-by-step explanation:

We are given that a sample of 81 account balances of a credit company showed an average balance of $1,200 with a standard deviation of $126.

We have test the hypothesis to determine whether the mean of all account balances is significantly different from $1,150.

<u><em>Let </em></u>\mu<u><em> = mean of all account balances</em></u>

(a)So, Null Hypothesis, H_0 : \mu = $1,150     {means that the mean of all account balances is equal to $1,150}

Alternate Hypothesis, H_A : \mu \neq $1,150    {means that the mean of all account balances is significantly different from $1,150}

The test statistics that will be used here is <u>One-sample t test statistics</u> as we don't know about population standard deviation;

                               T.S.  = \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample average balance = $1,200

             s = sample standard deviation = $126

             n = sample of account balances = 81

(b) So, <u>test statistics</u>  =  \frac{1,200-1,150}{\frac{126}{\sqrt{81} } }  ~ t_8_0

                               =  3.571

The value of the sample test statistics is 3.571.

(c) <u>Now, P-value of the test statistics is given by the following formula;</u>

          P-value = P( t_8_0 > 3.571) = <u>Less than 0.05%</u>

Because in the t table the highest critical value for t at 80 degree of freedom is given between 3.460 and 3.373 at 0.05% level.

Now, since P-value is less than the level of significance as 5% > 0.05%, so we sufficient evidence to reject our null hypothesis.

Therefore, we conclude that the mean of all account balances is significantly different from $1,150.

8 0
3 years ago
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