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2 years ago

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Find the midpoint of the line segment whose endpoints are (-2, 5) and (4, -9).Find the midpoint of the line segment whose endpoi

nts are (-2, 5) and (4, -9).

1 answer:

jek_recluse [69]2 years ago

8 0

Answer:

The midpoint is $(1,-2)$

Step-by-step explanation:

we know that

The formula to calculate the midpoint between two points is equal to

$M(\frac{x1+x2}{2},\frac{y1+y2}{2})$

we have

$(x1,y1)=(-2,5)$

$(x2,y2)=(4,-9)$

substitute

$M(\frac{-2+4}{2},\frac{5-9}{2})$

$M(1,-2)$

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Help me with this problem !!!!!!!!!!

Mamont248 [21]

Answer:

Hi, your answer is y= $-\frac{1}{2} x$ -3

Step-by-step explanation:

We will use the slope-intercept formula which is

$\frac{y2-y1}{x2-x1}$

We will use two points in this case I'll use

(-2,-2) and (-8,1)

$\frac{1-(-2)}{-8-(-2)}$ = $-\frac{3}{6}$ which can be simplified as $-\frac{1}{2}$

Your Y will be -3

which your final answer will be y=-1/2x-3

Hope this helps :)

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klasskru [66]

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The equation P=6s represents the perimeter P of a regular hexagon with side length s. What is the perimeter of a regular hexagon

Verdich [7]

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Step-by-step explanation:

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2 years ago

Suppose a local manufacturing company claims their production line has a variance of less than 9.0. A quality control engineer d

Alexxx [7]

Answer:

$\chi^2 =\frac{35-1}{9} 2.12^2 =16.979$

$p_v =P(\chi^2$

If we compare the p value and the significance level provided we see that $p_v$ so on this case we have enough evidence in order to reject the null hypothesis at the significance level provided. And that means that the population variance is significantly lower than 9

Step-by-step explanation:

Notation and previous concepts

A chi-square test is "used to test if the variance of a population is equal to a specified value. This test can be either a two-sided test or a one-sided test. The two-sided version tests against the alternative that the true variance is either less than or greater than the specified value"

$n=35$ represent the sample size

$\alpha=0.01$ represent the confidence level

$s =2.12$ represent the sample deviation obtained

$\sigma_0 =3$ represent the value that we want to test

Null and alternative hypothesis

On this case we want to check if the population variance specification is lower than 9 and the deviation lower than 3, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 \geq 9$

Alternative hypothesis: $\sigma^2$

Calculate the statistic

For this test we can use the following statistic:

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

And this statistic is distributed chi square with n-1 degrees of freedom. We have eveything to replace.

$\chi^2 =\frac{35-1}{9} 2.12^2 =16.979$

Calculate the p value

In order to calculate the p value we need to have in count the degrees of freedom , on this case df= n-1= 35-1=34. And since is a left tailed test the p value would be given by:

$p_v =P(\chi^2$

In order to find the p value we can use the following code in excel:

"=CHISQ.DIST(16.979,34,TRUE)"

Conclusion

If we compare the p value and the significance level provided we see that $p_v$ so on this case we have enough evidence in order to reject the null hypothesis at the significance level provided. And that means that the population variance is significantly lower than 9

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3 years ago